21V – 20V2 – V4 = 80 → Eq. 1 -40V1 + 49V2 – 4V3 = 0 → Eq.2 -2V2 + 5V3 – 2V4 = 0 → Eq. 3 -3V1 – 6V3 + 11V4 = 0 → Eq. 4 Answer: V1 = 25.52V V2 = 22.05V V3 = 14.842V V4 = 15.055V

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Use the elimination method or Cramers rule (matrix) for solving the eq. 1,2,3 & 4 to get the correct answer which is already given. 

21V – 20V2 – V4 = 80 → Eq. 1
-40V, + 49V2 – 4V3 = 0 → Eq. 2
-2V2 + 5V3 – 2V4 = 0 → Eq. 3
-3V – 6V3 + 11V4 = 0 → Eq. 4
Answer:
V1 = 25.52V
V2 = 22.05V
V3 = 14.842V
V4 = 15.055V
Transcribed Image Text:21V – 20V2 – V4 = 80 → Eq. 1 -40V, + 49V2 – 4V3 = 0 → Eq. 2 -2V2 + 5V3 – 2V4 = 0 → Eq. 3 -3V – 6V3 + 11V4 = 0 → Eq. 4 Answer: V1 = 25.52V V2 = 22.05V V3 = 14.842V V4 = 15.055V
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