21. Calculate the enthalpy change, AH, for the following gas phase reaction using bond energy data. H H нн Bond Dissociation Energy | | H-C1 435 kJ/mol C= C +H- Cl Н-С- С-Н С-Н 413 kJ/mol | С-С 348 kJ/mol H H H CI C=C 614 kJ/mol C-C1 328 kJ/mol 2

(H2 + F2 --> 2 HF) Given the average bond energies for this reaction, calculate AH for the following reaction: [H-H = 432 KJ/mol], [F-F = 154 %3D KJ/mol], [H-F = 565 KJ/mol] * %3D -21 KJ 21 KJ 544 KJ -544 KJ 1151 KJ

What is the value of AH° for the following reaction? CF 4(g) + 2 H2ig) CH4(9) + 2 F29) The values of the bond energies are: C-H bond 413 kJ/mol, H-H bond 432 kJ/mol, F-F bond 159 kJ/mol, and C-F bond 485 kJ/mol. O-834 kJ O-854 kJ O 814 kJ 2894 kJ O-874 kJ Clear my choice Next page

Could you please explain #9-12 please, thank you.

Calculate the DHf for HBr in kJ/(mol HBr) using the bond energies given below.             H-H  436 kJ/mol          Br-Br  190 kJ/mol          H-Br  370 kJ/mol

Use the given bond energy values to estimate ΔH  for the following gas-phase reaction (see image attached)   D-values in kJ/mol DH-H = 432    DH-Br = 363    DH-C = 413 DH-N = 391    DH-O = 467    DC-C = 347 DC=C = 614    DC≡C = 839    DC-N = 305 DC=N = 615    DC≡N = 891    DC-O = 358 DC=O = 745    DC=O (CO2) = 799    DC≡O=1072 DC-Br = 276    DN-N = 160.    DN=N = 418 DN≡N = 941    DO-O = 146    DO=O = 495 DN-O = 201    DN=O = 607    DBr-Br = 193 DC-Cl = 339    DH-Cl = 427    DCl-Cl = 239   (Simple energy units required for the answer.)

How much energy (in kJ) is required to separate (break) one mole of H-H bonds?

* Question Completion Status: QUESTION 39 YOU MUST SUBMIT WORK FOR THIS PROBLEM INTO A SEPARATE ASSIGNMENT. Using the bond energies provided, calculate AHrxn° for: H. H H H Br-Br Br—с-с-Br H H. H Bond Bond energy (in kJ/mole) C-H 410 C-C 350 C-Br 270 C=C 611 Br-Br 194 AHrxn° of the following reaction is kJ. (Remember about correct sign) OUECTION 10

Only typed solution

Using bond energies and the energy change of the reaction, calculate the bond energy of the CO double bond. Do not round your answer. C3H8 is propane C3H8 + 5O2 → 3CO2 + 4H2O . Bond Energy(kJ/mol) C-H 411 C-C 346 O=O 495 O-H 459 Reaction energy(kJ) -2047