21 - What is the chi-square table value in an experiment with a significance level of 0.05, 5 groups and 7 observations? a) 5,99146 B) 9,48773 NS) 12,59159 D) 14,44938 TO) 7,77944
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21 - |
What is the chi-square table value in an experiment with a significance level of 0.05, 5 groups and 7 observations? |
|
Given,
c = 5
r = 7
We have to find Chi-square table value?
Step by step
Solved in 2 steps with 1 images
- 4. Please answer the blanks ty!!Spinning a coin, unlike tossing it, may not give heads and tails equal probabilities. I spun a penny 275 times and got 122 heads. We wish to find how significant is this evidence against equal probabilities. a. What is the sample proportion of heads? Round to 3 decimal places. b. Heads do not make up half of the sample. Is this sample evidence that the probabilities of heads and tails are different? Take p to be the probability of getting heads in a spin of a penny. Which hypotheses do we want to test? O Họ: p = 0.5 Họ: p > 0.5 O Ho: p = 0.5 Ho: p < 0.5 O Ho: p = 0.5 Ho: p 0.5 O Ho: p 0.5 Ho: p = 0.5 c. Compute the z test statistic. Z = Round to 2 decimal places.K A simple random sample of front-seat occupants involved in car crashes is obtained. Among 2905 occupants not wearing seat belts, 37 were killed. Among 7830 occupants wearing seat belts, 13 were killed. Use a 005 significance level to test the claim that seat belts are effective in reducing fatalities. Complete parts (a) through (c) below. OA. Ho: P1 SP2 H₁: P1 P2 OD. Ho: P1 = P2 H₁: P1 P2 Identify the P-value. Identify the test statistic. 2-0 (Round to two decimal places as needed.) 0-0 OB. Ho: P1 = P2 H₁: P1 P2 P-value M-.LTL 11144 OE. Ho: P1 P2 H₁ P1 = P2 OC. Ho P1 = P2 H₁: P1 P2 OF. Ho: P12 P2 H₁: P1 P2
- Dr. Garcia is curious about her teaching skills. To investigate, her class takes an anatomy quiz. The population average for the anatomy quiz is 15. What can be concluded with a = 0.10? The quiz scores for a random sample from the class are: 16, 17, 18, 16, 19, 15, 18. a) What is the appropriate test statistic? --Select-- b) Population: |---Select--- Sample: ---Select-- c) Obtain/compute the appropriate values to make a decision about Hn. Critical Value = ; Test Statistic = Decision: ---Select--- d) If appropriate, compute the CI. If not appropriate, input "na" for both spaces below. e) Compute the corresponding effect size(s) and indicate magnitude(s). If not appropriate, input and/or select "na" below. d = ; Magnitude: --Select--- ; Magnitude: --Select--- 2 = f) Make an interpretation based on the results. O Quiz scores for the class were significantly higher than the population. O Quiz scores for the class were significantly lower than the population. O Quiz scores from the class…3. Dentists make many people nervous. To assess any effect of such nervousness on blood pressure, the systolic blood pressure of 60 subjects was measured both in a dental setting and in a medical setting (The Effect of the Dental Setting on Blood Pressure Measurement," Amer. J. of Public Health, 1983:1210- 1214). For each subject, the difference between dental setting pressure and medical setting pressure was computed; the resulting sample mean difference and sample standard deviation of the differences were 4.47 and 8.77 mmHg, respectively. o (a) Estimate the true mean difference between blood pressures for these two settings using a 99% confidence level. o (b) Does it appear that the true mean pressure is different in a dental setting than in a medical setting? Explain your reasoning.In 2015, the average duration of long-distance telephone calls from a certain town was 3.9 minutes.A telephone company wants to perform a test to determine whether this average duration of longdistance calls has changed. Fifty calls, originating from the town, was randomly selected and thefollowing summary minutes.∑ ? = 205 ∑(? − ?̅)∑(? − ?̅)2 = 56.43 a) Calculate the sample mean, ?̅. b) Calculate the sample standard deviation c) Using the p value approach at the 1% level of significance, test whether the mean duration oflong-distance calls from the town had increased. d) Construct the 99% confidence interval for the population mean duration of the long-distance calls from the town. Answer sub-parts (d)
- Only 10% of registered voters voted in the last election. Will voter participation increase for the upcoming election? Of the 399 randomly selected registered voters surveyed, 52 of them will vote in the upcoming election. What can be concluded at the a = 0.01 level of significance? a. For this study, we should use Select an answer28A researcher assures that in his country, on average, the salary of workers is less than $5000.00. He takes a sample of 7 workers and finds that their salary is: $3900.00, $5100.00, $3100.00, $5500.00, $2700.00, $4500.00, $4100.00 Can you be sure at the 0.02 level of significance that the researcher is correct? Choose 1. The correct conclusion2. The correct interpretation Select one:to)1. H0 is rejected2. With a confidence of 98% it can be ensured that the average wage of the workers is not less than $5000.00b)1. H0 is not rejected2. With a confidence of 98% it can be ensured that the average wage of the workers is not less than $5000.00c)1. H0 is not rejected2. It can be ensured, with 98% confidence, that the average wage of the workers is less than $5,000.00d)1. H0 is rejected2. It can be ensured, with 98% confidence, that the average wage of the workers is less than $5,000.00
- 7. With a previous contractor, the mean time to replace a streetlight was 3.2 days. A city councilwoman thinks that the new contractor is not getting the streetlights replaced as quickly. She selects a random sample of 12 streetlight service calls for the new contractor, and obtains the following times to replacement (days). 6.2 7.1 5.4 5.5 7.5 2.6 4.3 2.9 3.7 0.7 5.6 1.7 Using a significance level of 0.01, test the councilwoman's claim. You may assume that all conditions are satisfied.Different chemicals are tested to check their effects on different cloth materials. The chemicals will be used in one of the finishing processes. Five cloth materials are selected for testing and four chemicals will be used on each cloth material sample. a) Are there significant differences between four different chemicals? ( = .05) b) Considering your answers in part a., perform the appropriate tests to determine which chemicals differ significantly.1.42 Sleeping in college: A recent article in a college newspaper stated that college students get an average of 5.5 hrs of sleep each night. A student who was skeptical about this value decided to conduct a survey by randomly sampling 25 students. On average, the sampled students slept 6.25 hours per night. Identify which value represents the sample mean and which value represents the claimed population mean. a) What is the sample mean? hours b) What is the claimed population mean? hours