20. In the circuit shown, initially the switch is open and all the capacitors are uncharged. Consider the first 100 s interval after the switch is closed. Find the total energy stored in the capacitors and the total energy dissipated in the resistance in this 100 s interval. Internal resistance of the battery does not exceed a few ohms. Ans: 9x10-2 J 1x10-2 C, = 3 µF C3 6 µF R=100 k2 C2 = 6 µF Vo 200 V C= 3 µF

Introductory Circuit Analysis (13th Edition)
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ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
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20. In the circuit shown, initially the switch is open and all the capacitors
are uncharged. Consider the first 100 s interval after the switch is
closed. Find the total energy stored in the capacitors and the total
energy dissipated in the resistance in this 100 s interval. Internal
resistance of the battery does not exceed a few ohms.
Ans: 9x10-2 J
1x10-2
C, = 3 µF
C3 6 µF
R=100 k2
C2 = 6 µF
Vo 200 V
C= 3 µF
Transcribed Image Text:20. In the circuit shown, initially the switch is open and all the capacitors are uncharged. Consider the first 100 s interval after the switch is closed. Find the total energy stored in the capacitors and the total energy dissipated in the resistance in this 100 s interval. Internal resistance of the battery does not exceed a few ohms. Ans: 9x10-2 J 1x10-2 C, = 3 µF C3 6 µF R=100 k2 C2 = 6 µF Vo 200 V C= 3 µF
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