20. In the circuit shown, initially the switch is open and all the capacitors are uncharged. Consider the first 100 s interval after the switch is closed. Find the total energy stored in the capacitors and the total energy dissipated in the resistance in this 100 s interval. Internal resistance of the battery does not exceed a few ohms. Ans: 9x10-2 J 1x10-2 C, = 3 µF C3 6 µF R=100 k2 C2 = 6 µF Vo 200 V C= 3 µF

Can someone help with these worksheets and let me know if have any incorrect answers? Thank you

Can you help me one image is the answer and the second image is the question but I don't fully understand the answer that my teacher gave me could you maybe give me another perspective

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