20. A 5 kg block is pulled along a rough level surface by a pull force P, where P = 300 N. The figure shows the free-body diagram for the block, fk represents the force of kinetic friction. If the coefficient of kinetic friction between the block and the surface, k = 0.3, calculate the magnitude of the block's acceleration? Hint: Obtain two equations from Newton's second law, only one of them directly involve acceleration but you will still need the other equation. FN fko.? 3 5kg mg 300N olay ontos antiga P ΣFx = max= P_-4₁₂² = Max {Fy=may = FN-pg = mal FN-g=a el or sups P-MR₂ = m (FN Мк

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ung on it
E have no frictional force acting on it
20. A 5 kg block is pulled along a rough level surface by a pull force P, where P = 300 N. The figure shows the
free-body diagram for the block, fk represents the force of kinetic friction. If the coefficient of kinetic
friction between the block and the surface, k = 0.3, calculate the magnitude of the block's acceleration?
Hint: Obtain two equations from Newton's second law, only one of them directly involve acceleration but
you will still need the other equation.
FN
A)
B)
D)
E)
on
k03)
25 m/s²
57 m/s²
285 m/s²
315 m/s²
none of the above
5kg||
Infin
rusrail 22
mg
P-MK =
m
nevytipolov antar ont igau
300N
->)
EFx = max = P₂
= max
-MK
{Fy=may = FN-ong = ma
FN-g=a
ov
P-M₁₂ = m (FN
Мк=
300-0.3-5kg (F
→ P
=ma
ei
ant ell or supe zi joalde
jogido na orelor
BOR
(0
300-0.3
5
1. Two forces act on a 4.5-kg block resting on a frictionless surface as shown. What is the magnitude
horizontal acceleration of the block? Hint: There are two forces along the x-direction
Transcribed Image Text:ung on it E have no frictional force acting on it 20. A 5 kg block is pulled along a rough level surface by a pull force P, where P = 300 N. The figure shows the free-body diagram for the block, fk represents the force of kinetic friction. If the coefficient of kinetic friction between the block and the surface, k = 0.3, calculate the magnitude of the block's acceleration? Hint: Obtain two equations from Newton's second law, only one of them directly involve acceleration but you will still need the other equation. FN A) B) D) E) on k03) 25 m/s² 57 m/s² 285 m/s² 315 m/s² none of the above 5kg|| Infin rusrail 22 mg P-MK = m nevytipolov antar ont igau 300N ->) EFx = max = P₂ = max -MK {Fy=may = FN-ong = ma FN-g=a ov P-M₁₂ = m (FN Мк= 300-0.3-5kg (F → P =ma ei ant ell or supe zi joalde jogido na orelor BOR (0 300-0.3 5 1. Two forces act on a 4.5-kg block resting on a frictionless surface as shown. What is the magnitude horizontal acceleration of the block? Hint: There are two forces along the x-direction
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