20-m pipe has an outside diameter of 50 mm. Pipe is insulated with a layer ofasbestos, then followed by a layer of cork. Inside and outside diameter of thecork is 77 mm and 80 mm, respectively. If the temperature drop from pipe tocork is 1165°C, calculate the inside diameter of the pipe (mm). The rate of theheat transfer is 8778 W. The thermal conductivity of steam pipe, asbestos andcork are 0.045 kW/m-K, 0.058 W/m-K and 0.043 W/m-K respectively.

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Answered: 20-m pipe has an outside diameter of 50…

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

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1) A wall section composed from the outside to inside, of concrete brick 100mm thick, an air space of 50mm, two layers of fiberglass insulation 38mm thick, concrete block 150mm thick and air space of 19mm and a gypsum board of 13mm. The exterior conditions are -20C and RH=90% while the interior conditions are 23C and RH=40%. The surface temperature from the outside to inside are shown in the figure. The permeances are: Still Air: µ = 175 ng/pa.s.m Fiber glass: M=2560 ng/pa.s.m? Concrete block: M= 200 ng/pa.s.m? Gypsum board: M= 2000 ng/pa.s.m? Concrete brick: µ = 4.55 ng/pa.s.m Determine if there is a risk of condensation, and if there is, what is the condensation rate? What would happen if a vapor barrier (M=0.2 ng/pa.s.m²) was installed on the warm side of the insulation (Surface 4). 21с 19C 16 С 12C -10 -15C -18C -19C Gyp Air Concrete Fiber Fiber Air Concrete Outdoor Indoor sum block Glass Glass brick 230 19 50 mm -20C 13 150 mm 38 mm | 38 mm 100 mm RH=90% RH=40% mm mm Surf. 1 Surf.…
Steel pipe (outer diameter 100 mm) is covered with two layers of insulation. The inner layer, 40 mm thick, has a thermal conductivity of 0.07 W / (m K). The outer layer, 20 mm thick, has a thermal conductivity of 0.15 W / (m K). Pipes are used to deliver steam with a pressure of 800 kPa. The temperature on the outer insulation surface is 24 ° C. If the pipe is 10 m long, determine the following: (assuming that the conduction heat transfer resistance of the steel pipe and the vapor convection resistance are negligible). a. Heat loss per hour. = Answer kJ / hour. b. Temperature between insulation layers. = Answer ° C.
1- Microwave radiation is incident on one side of a planar wall with a heat conductivity coefficient k. (x=0) -D°b=(x)b leads to volumetric heating. While this surface is 9(W/m²) microwave radiation is fixed. kept at a constant temperature To, the other surface at x=L is very well insulated. Determine the temperature distribution T(x) in terms of x, L, k, qo and To.
As2 Calculate the temperature 7 cm into the mineral wool layer from the warm side measured in one wall that is built from the outside in according to the following material layers: Wood panel ventilated R = 0.20 m2K / W Mineral wool 200 mm λ = 0.033 W / mK Plastic foil R ≈ 0 m2K / W Plasterboard 13 mm λ = 0.22 W / mK The temperature outside is -10 ◦C and inside 22 ◦C. The heat transfer resistors are on the inside Rsi = 0, 13 and on the outside Rse = 0, 04 m2K / W
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If a heat transfer coefficient of 2.84 W l(m2 • K) exists on each of the two inside faces of two sheets of 6.35-mm-thick glass separated by an air gap, calculate the gap that can be used such that the rate of heat transfer by conduction through the air gap equals the rate of heat transfer by convection. What is the rate of heat transfer if this gap is exceeded. The thermal conductivity of air of 0.0242 WI (m . K). Solve for temperature of 20°C and 12°C on the outside surfaces of the glass. Would the calculated gap change in value for different values of the surface temperatures? Would there be any advantage to increasing the gap beyond this calculated value?
A temperature difference of 85°C is impressed across a fiberglass layer of 13 cm thickness. The thermal conductivity of the fiberglass is 0.035 W/m °C. Compute the heat transferred through the material per hour per unit area.
A wall as given in fig is made up of two layers (A) and (B) The temperatures are as shown in the sketch. The ratio of thermal conductivities of two layers is given as KA = 3 the ratio t, : t, is KB T2 = 1200 T, = 1300° C B T3 = 30 A
A hot water pipe is used for domestic applications is insulated with a layer of calcium silicate. If the insulation is 25 mm thick and its inner and outer surfaces are maintained at Ts,1 = 800 K and Ts,2 = 400 K, respectively. The outside diameter is 0.12 m. Calculate the heat loss per unit length of the pipe. Given the thermal conductivity of calcium silicate insulation equals to 0.09 W/m.K.

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