Using the free-body diagram shown below, determine the support reactions Ay and By.20 kipsAxA30 kips3 kips/ftBByExpress your answers, separated by a comma, to the nearest integer.▸ View Available Hint(s)ΜΕ ΑΣΦvecAy =, By?kips, kips 20 kips30 kips3 kips/ftA4 ft-BT12 ft4 ftThe distance from point A to point B is 20 ft, adistributed load of 3 kips/ft exists between A and B,a point load of 20 kips is applied 4 ft to the right ofpoint A, and a point load of 30 kips is applied 4 ft tothe left of point B.

Answered: Image /qna-images/answer/2ca50ee2-cbd5-46f1-8fab-4ae9fd449ab5.jpg

Answered: Using the free-body diagram shown…

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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The safe load, L, of a wooden beam of width w, height h, and length l, supported at both ends, varies directly as the product of the width and the square of the height, and inversely as the length. A wooden beam 44inches wide, 77inches high, and 168168inches long can hold a load of 62006200pounds. What load would a beam 5inches wide, 8inches high, and 240inches long, of the same material, support? Round your answer to the nearest integer if necessary.
A spiral column carries a dead load of 1070 kN and a live load of 980 kN. If fc' = 27.50 MPa Fy = 413.50 MPa. Use U = 1.2D + 1.6L, Ф = 0.65, ρ = 0.01 1. Which of the following gives the value of the diameter of spiral column. a. 440 mm b. 420 mm c. 450 mm d. 510 mm 2. Which bar size will provide least number of pieces allowed?. a. 16 mm b. 22 mm c. 20 mm d. 25 mm 3. Which of the following gives the possible spacing of the 10 mm0 spirals. a. 30 mm b. 40 mm c. 60 mm d. 60 mm
Please Answer it fast on Sheet of paper. F1=1.5KN ,F2=3.8KN, a=3.6m ,b=2.0m ,c=1.3m. You need to find Forces in member (CH,AH and CD) And whether it's +ve or -ve.
1. A simply supported 5 meter timber beam carries a 5kN/m uniformly distributed load. If the beam’s Ix is 260.4166 x 10^6 mm^4 and fb= 7.50 MPa, the maximum moment development is? a) 14.656 kN-m b) 15.625 kN-m c) 16.625 kN-m d) 17.625 kN-m 2. What is VMax for the beam of question 1? a) 10.5 kN b) 11.5 kN c) 12.5 kN d) 13.5 kN 3. What is the beam’s depth of question 1? a) 180 mm b) 200 mm c) 220 mm d) 250 mm
The service load bending moments actong on a rectangular beam 310 mm wide and 624 mm deep are 58.35 kN-m for dead load and 69.11 kN-m for live load. Use the following properties: f'c = 30.01 MPa fy = 414 MPa p= 0.81 pbal db = 20 mm (bar diameter) ds = 10 mm (strirrups diameter) Consider the stirrups used are spiral stirrups. Calculate the D/C ratio in percentage (%) for the particular beam.
load A =350 N load b=400 N
A simply supported rectangular beam of length 6.45m has a width of 390.5mm and an effective depth of610.5mm. The beam is to be reinforced using 12 ?? bars. The beam supports service dead loads ofWd = 13.5kN/m and WL = 35.5kN/m. f'c = 28Mpa and fy=420 MPa Given: b= 390.5 mm d= 610.5mm L= 6.45 m Wd = 13.5 kN/m WL = 35.5 kN/m 1. Calculate the ultimate moment capacity of the beam.2. Calculate the height of the equivalent stress block.3. Determine the number of bars required for this beam.
*subject: civil engineering - Reinforced prestressed concrete *please refer attached picture formula A square tied column to support an axial dead loadof 529 kN and axial live load of 663 kN. fc'=25.72MPa, fy = 332 MPa, gross P= 0.028. The no. of 23mmbars to be used is ___pieces. round off zero decimal places
A short tied column carries an axial dead load of 1070 kN and live load of 981 kN. If fc' = 27.50 MPa, fy = 413.50 MPa. 1. Which of the following gives the probable size of the tied column. a. 400x400 b. 300x300 c. 500x500 d. 550x550 2. Which of the following gives the number of 28 mm diameter main reinforcing bars. a. 4 bars b. 8 bars c. 6 bars d. 10 bars 3. Which of the following gives the spacing of 10 mm tie wires. a. 300 mm b. 350 mm c. 400 mm d. 500 mm
Please help with this practice question. Thanks Question 1 ) determine the counterweight J in order for the main jib DCB to be horizontal. (The units should be in kN)
Can someone please solve this? Find load function functions and draw load effect diagrams? Fx=4.5KN.Fz=2.5 KNMB = 2.5 KNm.a= 1.6M.
Given: Mmax= 15.625 kN-m Vmax= 12.5 kN Depth of the beam= 250 mm 1. A simply supported 5 meter timber beam carries a 5 kN/m uniformly distributed load. If the beam's Ix is 260.4166 x 10^6 mm^4 and fb = 7.50 MPa, what is the base of the beam? a) 150 mm b) 180 mm c) 200 mm d) 220 mm 2. The shear stress fv developed for the beam of question 1 is a) 0.375 MPa b) 0.50 MPa c) 0.75 MPa d) 0.85 MPa

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