2.000 g TUMS tablet (CaCO3 and Binder) was analyzed in a lab. 11.42 mL of 0.871 M HCI was needed to dissolve the CaCO3 (active ingredient) of TUMS Tablet. Find the mass and % by mass of CaCO3 in TUMS Tablets. 459.00 mg O 75% O 50% 605.00 mg 30% O 25% 0 400.00 mg O 500.00 mg

2.000 g TUMS tablet (CaCO3 and Binder) was analyzed in a lab. 11.42 mL of 0.871 M HCI was needed to dissolve the CaCO3 (active ingredient) of TUMS Tablet. Find the mass and % by mass of CaCO3 in TUMS Tablets. 459.00 mg O 75% O 50% 605.00 mg 30% O 25% 0 400.00 mg O 500.00 mg

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Question

100%

2.000 g TUMS tablet (CaCO3 and Binder) was analyzed in a lab.
11.42 mL of 0.871 M HCI was needed to dissolve the CaCO3 (active
ingredient) of TUMS Tablet. Find the mass and % by mass of CaCO3 in
TUMS Tablets.
( 459.00 mg
O 75%
50%
605.00 mg
30%
O 25%
O 400.00 mg
O 500,00 mg

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