Calculus: Early Transcendentals
Calculus: Early Transcendentals
8th Edition
ISBN: 9781285741550
Author: James Stewart
Publisher: Cengage Learning
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Below is the transcribed mathematical expression suitable for an educational website:

\[ 
2. \int_{1}^{2} \int_{3}^{4} \sqrt{xy} \, dy \, dx = \int_{1}^{2} \sqrt{x} \, dx \int_{3}^{4} \sqrt{y} \, dy 
\] 

### Explanation:

This expression represents the equality of two iterated integrals. The left side involves integrating the function \(\sqrt{xy}\) first with respect to \(y\) from 3 to 4, and then with respect to \(x\) from 1 to 2. The right side separates the integration into a product of two integrals: one for \(\sqrt{x}\) with respect to \(x\) from 1 to 2, and the other for \(\sqrt{y}\) with respect to \(y\) from 3 to 4.

This equality demonstrates how the integration of a function of two variables can sometimes be separated into simpler integrals when the function can be expressed as a product of single-variable functions.
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Transcribed Image Text:Below is the transcribed mathematical expression suitable for an educational website: \[ 2. \int_{1}^{2} \int_{3}^{4} \sqrt{xy} \, dy \, dx = \int_{1}^{2} \sqrt{x} \, dx \int_{3}^{4} \sqrt{y} \, dy \] ### Explanation: This expression represents the equality of two iterated integrals. The left side involves integrating the function \(\sqrt{xy}\) first with respect to \(y\) from 3 to 4, and then with respect to \(x\) from 1 to 2. The right side separates the integration into a product of two integrals: one for \(\sqrt{x}\) with respect to \(x\) from 1 to 2, and the other for \(\sqrt{y}\) with respect to \(y\) from 3 to 4. This equality demonstrates how the integration of a function of two variables can sometimes be separated into simpler integrals when the function can be expressed as a product of single-variable functions.
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