Algebra and Trigonometry (6th Edition)
Algebra and Trigonometry (6th Edition)
6th Edition
ISBN: 9780134463216
Author: Robert F. Blitzer
Publisher: PEARSON
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**Question:**

2. Which is the graph of the quadratic equation \( y = -3x^2 + x + 1 \)?

**Options:**

a. ![Graph a](graph_a)
   - The graph shows a downward-opening parabola centered slightly to the right of the y-axis. The vertex appears below the x-axis, indicating a maximum point since the parabola opens downwards.

b. ![Graph b](graph_b)
   - This graph displays an upward-opening parabola with a vertex above the x-axis. The parabola is centered slightly to the left of the y-axis.

c. ![Graph c](graph_c)
   - Here, the graph depicts a downward-opening parabola. The vertex is located near the y-axis, representing a maximum point.

d. ![Graph d](graph_d)
   - This graph illustrates an upward-opening parabola with its vertex positioned above the x-axis, slightly right of the y-axis.

**Explanation:**

For the quadratic equation \( y = -3x^2 + x + 1 \), we need to identify a downward-opening parabola due to the negative coefficient of \( x^2 \). The most likely graph is option (a) or (c), as they both open downward. Given the structure of the equation, the correct graph shares characteristics with these descriptions based on the vertex and direction of opening.
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Transcribed Image Text:**Question:** 2. Which is the graph of the quadratic equation \( y = -3x^2 + x + 1 \)? **Options:** a. ![Graph a](graph_a) - The graph shows a downward-opening parabola centered slightly to the right of the y-axis. The vertex appears below the x-axis, indicating a maximum point since the parabola opens downwards. b. ![Graph b](graph_b) - This graph displays an upward-opening parabola with a vertex above the x-axis. The parabola is centered slightly to the left of the y-axis. c. ![Graph c](graph_c) - Here, the graph depicts a downward-opening parabola. The vertex is located near the y-axis, representing a maximum point. d. ![Graph d](graph_d) - This graph illustrates an upward-opening parabola with its vertex positioned above the x-axis, slightly right of the y-axis. **Explanation:** For the quadratic equation \( y = -3x^2 + x + 1 \), we need to identify a downward-opening parabola due to the negative coefficient of \( x^2 \). The most likely graph is option (a) or (c), as they both open downward. Given the structure of the equation, the correct graph shares characteristics with these descriptions based on the vertex and direction of opening.
### Graph of a Quadratic Equation

**Question:**  
Which is the graph of the quadratic equation \( y = -(x - 3)^2 - 1 \)?

**Options:**

**a.**  
Graph 1: This graph is a downward-facing parabola. The vertex is located in the positive region of the x-axis and in the negative region of the y-axis.

**b.**  
Graph 2: This graph is a downward-facing parabola. The vertex is located closer to the origin, with both x and y slightly negative.

**c.**  
Graph 3: This is an upward-facing parabola. The vertex is located in the positive region of the x-axis and in the negative region of the y-axis. The parabola is symmetric about the vertical line passing through the vertex.

**d.**  
Graph 4: This is an upward-facing parabola. The vertex is centered on the y-axis with a positive y value.

**Explanation:**  
The given equation is in vertex form \( y = a(x - h)^2 + k \), where \( (h, k) \) is the vertex. For the equation \( y = -(x - 3)^2 - 1 \), the vertex is at \( (3, -1) \) and the parabola opens downwards due to the negative sign before the squared term. Based on this analysis, graph **a** correctly represents the equation.
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Transcribed Image Text:### Graph of a Quadratic Equation **Question:** Which is the graph of the quadratic equation \( y = -(x - 3)^2 - 1 \)? **Options:** **a.** Graph 1: This graph is a downward-facing parabola. The vertex is located in the positive region of the x-axis and in the negative region of the y-axis. **b.** Graph 2: This graph is a downward-facing parabola. The vertex is located closer to the origin, with both x and y slightly negative. **c.** Graph 3: This is an upward-facing parabola. The vertex is located in the positive region of the x-axis and in the negative region of the y-axis. The parabola is symmetric about the vertical line passing through the vertex. **d.** Graph 4: This is an upward-facing parabola. The vertex is centered on the y-axis with a positive y value. **Explanation:** The given equation is in vertex form \( y = a(x - h)^2 + k \), where \( (h, k) \) is the vertex. For the equation \( y = -(x - 3)^2 - 1 \), the vertex is at \( (3, -1) \) and the parabola opens downwards due to the negative sign before the squared term. Based on this analysis, graph **a** correctly represents the equation.
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