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2. Three masses are located in the corners of an equilateral triangle. Find the magnitude and direction gravitational field at the center of the triangle. Given: m1 = 22 kg, m2 = 30 kg, m3 = 30 kg, r= 12 cm. G = 6.674 x 10-11 N•m2/kg2.
3. Four masses are at the vertices of a square. Find the magnitude of the gravitational force on the mass m1. Given: m1 = 6 kg, m2 = 80 kg, m3 = 80 kg, m4 = 80 kg, r = 24 m. G = 6.674 x 10-11 N•m2/kg2.
4. Four masses are located in the corners of a square. Calculate the magnitude and direction of the gravitational field at the center of the square. Given: m1 = 85 kg, m2 = 3 kg, m3 = 3 kg, m4 = 85 kg, r = 8 m. G = 6.674 x 10-11 N•m2/kg2.
5. Two masses m1 = 350 kg and m2 = 350 kg are at a distance of 22 m from each other. Find the magnitude and direction of the gravitational field at a point A. Data: h = 9m, G = 6.674 x 10-11 N•m2/kg2
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- 5. Two objects, with masses m1 and m2, are originally a distance r apart. The gravitational force between them has a magnitude F. The second object has its mass changed to 6m2, and the distance is changed to r/3. What is the ratio between the magnitude of the new gravitational force and F?(G = 6.67 a numerical value. 10-1N.m2/kg2). You must type your answer a f60 ssfc 160 ssi 0 ssf60arrow_forwardEvery few months, memes circulate claiming that certain alignments of the planets with the Earth will result in a change in the gravitational force you feel. Usually, these memes state that the alignment will counteract Earth's gravity slightly so you will feel less of a gravitational pull towards the Earth. Can this ever happen? Let's look at the numbers. What is the gravitational force (in N) of the Earth on you (ME = 5.97 ✕ 1024 kg, RE = 6380 km)? Say your mass is 68 kg. (Enter the magnitude.) What is the gravitational force (in N) of Jupiter on you when it is closest to Earth (MJ = 1.90 ✕ 1027 kg, RJE = 5.88 ✕ 108 km)? (Enter the magnitude.) By what factor would the mass of Jupiter need to increase to be equal to the gravitational force you feel from the Earth? Part 1 of 5 The gravitational force between two masses is given by Fg = −GMm r2 where G = 6.67 ✕ 10−11 m3/s2/kg. We can use this expression to determine the magnitude of the gravitational force you feel…arrow_forward6. What is the magnitude of the gravitational force that the sun exerts on Mercury? Use 3.29 × 1023 kg for the mass of Venus, 2.00 x 1030 kg for the mass of the Sun, and 6.10 x 10¹0 m for the distance between them.arrow_forward
- The diagram below shows three masses at the corners of a square of sides d = 3.10 m. Here, m, = m2 = m and m3 = 4.10m where m = 2.00 kg. m2 m3 d m (a) What is the magnitude of the gravitational field at the center of the square due to these three masses? m/s2 (b) Suppose the two masses m, and m, are not equal. What value of m, will produce a gravitational field at the center of the square directed vertically down? kg Additional Materialsarrow_forwardA wildlife preserve has two elephants. One has a mass of 6140 kg. The other has a mass of 4020 kg. What is the gravitational attraction between the elephants when they are 17 m apart? A. 9.7 x 10-5 N B. 5.7 x 10-6 N C. 8.5 x 104 N D. 5.6 x 1016 Narrow_forwardThe masses and coordinates of three spheres are as follows: 24 kg, x = 2.1 m, y = 0 m; 54 kg, x = -2.1 m, y = 0 m; 220 kg, x = 0 m, y = 2.4 m. What is the magnitude of the gravitational force on a 84 kg sphere located at the origin due to the other spheres? Number i 0.0000014 Units Narrow_forward
- Q2, Q3, and Q5arrow_forward1. A 104 kg person and their 10 kg dog are 12.5 m away from each other. If you approximate them both as perfectly spherical what if the attractive gravitational force between them? Use G = 6.67×10-11 N-m²/kg² Enter to 3 significant figures Fa grav 4.44×10 11X N No, that's not the correct answer.arrow_forward2. Determine the following. a. What is the acceleration due to gravity on the surface of the Moon? Hint: see index D in the textbook for the necessary values needed. b. On the surface of Mars? The mass of Mars is 6.418 × 1023 kg and its radius is 3.38 × 106 m.arrow_forward
- a.) Find the net force on the Moon (mM=7.35×1022kg)(mM=7.35×1022kg) due to the gravitational attraction of both the Earth (mE=5.98×1024kg)(mE=5.98×1024kg) and the Sun (mS=1.99×1030kg)(mS=1.99×1030kg), assuming they are at right angles to each other (Figure 1). Express your answer to three significant figures and include the appropriate units. Fnet= __________ ____________ b.) Determine the direction of the net force. Express your answer to three significant figures and include the appropriate units. θ= ______________ ___________arrow_forward1. Every particle in the universe attracts every other particle with a force that is proportional to the product of their masses and inversely proportional to the square of the distance between them. This force acts along the line joining the two particles. The magnitude of the gravitational force can be written as 2. A 87-kg person and a 78-kg object are near each other. Estimate the magnitude of the gravitational force each exerts on the other. APPROACH This is an estimate: we let the distance between the centers of the two objects be 41.0 m. FG = _____ (Units) 3. A 83-kg person and a 61-kg object are near each other. Estimate the magnitude of the gravitational force each exerts on the other. APPROACH This is an estimate: we let the distance between the centers of the two objects be 39 m. FG = _____ (Units 4. A 65-kg person and a 75-kg object are near each other. Estimate the magnitude of the gravitational force each exerts on the other. APPROACH This is an estimate: we let the…arrow_forwarda) i. b) i. Define gravitational field strength at a point. Determine the mass of the Earth assuming that it is a uniform sphere of radius 6378 km and that the gravitational field strength at the Earth's surface is 9.81 N kg¹¹. Determine the average density of the Earth. iii. Use the mass of the Earth as calculated in part b)i to determine the gravitational field strength due to the Earth at a distance of 3.5 x 108 m from the centre of the Earth. ii. iv. Consider a point X a distance of 3.5 x 108 m from the centre of the Earth and which lies on the line joining the centre of the Earth to the centre of the Moon. c) i. ii. At X the gravitational field strength due to the Moon is equal but opposite to that of the Earth. The mass of the Moon is 7.4 x 10²2 kg. Determine the distance from the centre of the Moon to X and hence determine the distance between the centres of the Earth and Moon. Determine the time in Earth years for the planet Jupiter to complete one orbit of the Sun. Take 1…arrow_forward
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