2. The volume of a tissue box is represented by the polynomial 2z4-32² +42-9. If the height of the tissue box is z+2, what is the area of the base of the tissue box? O2z³+4x²+5z+14+2 2z³+2+2- 2z²³-42² +52-6+ O22²³ +7x+18+

Algebra and Trigonometry (6th Edition)
6th Edition
ISBN:9780134463216
Author:Robert F. Blitzer
Publisher:Robert F. Blitzer
ChapterP: Prerequisites: Fundamental Concepts Of Algebra
Section: Chapter Questions
Problem 1MCCP: In Exercises 1-25, simplify the given expression or perform the indicated operation (and simplify,...
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**Problem Statement:**

The volume of a tissue box is represented by the polynomial \(2x^3 - 3x^2 + 4x - 9\). If the height of the tissue box is \(x + 2\), what is the area of the base of the tissue box?

**Options:**

A) \(2x^2 + 4x + 5 + \frac{14}{x + 2}\)

B) \(2x^2 + x + 2 - \frac{15}{x + 2}\)

C) \(2x^2 - 4x + 5x - 6 + \frac{1}{x+2}\)

D) \(2x^3 + 7x + 18 + \frac{27}{x+2}\)
Transcribed Image Text:**Problem Statement:** The volume of a tissue box is represented by the polynomial \(2x^3 - 3x^2 + 4x - 9\). If the height of the tissue box is \(x + 2\), what is the area of the base of the tissue box? **Options:** A) \(2x^2 + 4x + 5 + \frac{14}{x + 2}\) B) \(2x^2 + x + 2 - \frac{15}{x + 2}\) C) \(2x^2 - 4x + 5x - 6 + \frac{1}{x+2}\) D) \(2x^3 + 7x + 18 + \frac{27}{x+2}\)
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