2. The rate constant of a reaction at 32.0°C is 0.0550 s¹. If the frequency factor is 1.20 x 10¹3 s¹, what is the activation energy?

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**Question 2: Determining Activation Energy**

At 32.0°C, the rate constant of a reaction is 0.0550 s⁻¹. Given that the frequency factor is 1.20 x 10¹³ s⁻¹, calculate the activation energy.

---

To solve this problem, you can use the Arrhenius equation:

\[ k = A e^{-E_a/(RT)} \]

Where:
- \( k \) is the rate constant,
- \( A \) is the frequency factor,
- \( E_a \) is the activation energy,
- \( R \) is the universal gas constant (8.314 J/mol·K),
- \( T \) is the temperature in Kelvin.

**Steps to solve:**
1. Convert the given temperature from Celsius to Kelvin by adding 273.15.
2. Rearrange the Arrhenius equation to solve for the activation energy \( E_a \).
3. Substitute the given values and constants into the equation.
4. Solve for \( E_a \).

Note: Pay careful attention to units throughout the calculation to ensure accuracy.
Transcribed Image Text:**Question 2: Determining Activation Energy** At 32.0°C, the rate constant of a reaction is 0.0550 s⁻¹. Given that the frequency factor is 1.20 x 10¹³ s⁻¹, calculate the activation energy. --- To solve this problem, you can use the Arrhenius equation: \[ k = A e^{-E_a/(RT)} \] Where: - \( k \) is the rate constant, - \( A \) is the frequency factor, - \( E_a \) is the activation energy, - \( R \) is the universal gas constant (8.314 J/mol·K), - \( T \) is the temperature in Kelvin. **Steps to solve:** 1. Convert the given temperature from Celsius to Kelvin by adding 273.15. 2. Rearrange the Arrhenius equation to solve for the activation energy \( E_a \). 3. Substitute the given values and constants into the equation. 4. Solve for \( E_a \). Note: Pay careful attention to units throughout the calculation to ensure accuracy.
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