2. The mean distance between the earth and the sun is 1.5 x 1011m. The mean distance between the sun and Venus is 1.08 x 108km. What is the period of Venus around the sun in earth-days?
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- What, on a sphere, is analogous to a two-dimensional Cartesian coordinate system?2. The mean distance between the earth and the sun is 1.5 x 1011m. The mean distance between the sun and Venus is 1.08 x 108km. What is the period of Venus around the sun in earth- days?8. The mean distance of Earth from the Sun is 149.6 x 10° km and the mean distance of Mercury from the Sun is 57.9 x 10° km. The period of Earth's revolutions is 1 year, what is the period of Mercury's revolution? a. 0.24 year on Earth b. 0.42 year on Earth C. 1.13 year on Earth d. 1.31 year on Earth 9. The planet Delta has 2 times the gravitational field strength and 3 times the radius of Earth. How does the mass of the planet Delta compare with the mass of Earth?
- 25. The mean distance of Earth from the Sun is 149.6 x 10° km and the mean distance of Mercury from the Sun is 57.9 x 106 km. The period of Earth's revolutions is 1 year, what is the period of Mercury's revolution? a. 0.24 year on Earth b. 0.42 year on Earth C. 1.13 year on Earth d. 1.31 year on Earth3. What is the period T of a planet which radius is as twice as of Earth when it completes one revolution in 875 days? (Earth radius = 6.38 x 105)8. Calculate the period of Mercury around the Sun using the Earth's period and orbital radius as a reference. (TES 1.50×10¹¹ m, MS = 5.79×10¹0 m)
- 1. The earth has a mass of 5.97219 x 1024 kilograms and a radius of 3958.8 mi. If you have a mass of 145.505 Ibs, how strong is the force between you and the moon in MKS units? 2. A distance of 0.002 m separates two objects of equal mass. If the gravitational force between them is 0.0104 N, find the mass of each object. 3. What will be the radial acceleration will a satellite attain if NASA was instructed to deploy a 2000-kg satellite into our orbit 186 mi above the surface of the earth? Use the data given in number 1.1. Compute for the value of the acceleration due to gravity g of an object at an altitude equal to twice the radius of the Earth? (radius of Earth = 6.4 x 106 m) 2. Scientists once hypothesized the existence of a planet called Vulcan to explain Mercury's precession. Vulcan is supposed to be between Mercury and the Sun with a solar distance equal to 2/3 of that of Mercury. What would be its supposed period? 3. What is the period T of a planet which radius is as twice as of Earth when it completes one revolution in 875 days? ( Earth radius = 6.38 x 105) %3D %3D2. Suppose a small planet is discovered that is 14 times as far from the sun as the Earth's distance is from the sun (1.5 x 10" m). Use Kepler's law of harmonies to predict the orbital period of such a planet. GIVEN: T?/R³ = 2.97 x 1019 s²/m³
- 1. The average distance between Earth and the Sun is 1.5 × 108 km. (a) Calculate the average speed of Earth in its orbit (assumed to be circular) in meters per second. (b) What is this speed in miles per hour?1. Compute for the value of the acceleration due to gravity of an object at an altitude equal to twice the radius of the Earth? (radius of Earth = 6.4 x 10^6 m) 2. Scientists once hypothesized the existence of a planet called Vulcan to explain Mercury’s precession. Vulcan is supposed to be between Mercury and the Sun with a solar distance equal to 2/3 of that of Mercury. What would be its supposed period? 3. What is the period T of a planet which radius is as twice as of Earth when it completes one revolution in 875 days? (Earth radius = 6.38 x 10^5)A climber who is 75 kgs in mass reaches the peak of a mountain. If the mutual attraction between the climber and the Earth is 735.09 N, how tall is the mountain in meters? radius of the Earth = 6.38 x 106 m mass of the Earth = 5.98 x 1024 kgs