2. The equation of electric charge on the capacitor is related to the equation of currentstrength with the equation i=dq/dt. So, the equation forms a second-order differentiald²qdq1Ldt+ R,+79 = E(t)dtequation. Determine the special charge equation with the equation q(t) on the capacitor inthe RLC circuit when the value of L= 0.25 Henry,R=10 ohms,C=0.001 Farads,E(t)=0,q(0)=q0coulombs(C) and i(0)=0 Ampere.

Given the differential equation in RLC circuit as : Ld2qdt2+Rdqdt+1Cq=E(t) Given: R=10 Ω, L=0.25 H,…

Answered: 2. The equation of electric charge on…

Introductory Circuit Analysis (13th Edition)

13th Edition

ISBN:9780133923605

Author:Robert L. Boylestad

Publisher:Robert L. Boylestad

Chapter1: Introduction

Section: Chapter Questions

Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...

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Similar questions

When the capacitor is charged current flows on either side of the capacitor. Do electrons cross the gap to allow the current on the other side of the circuit?(b) Is charging and discharging time of capacitor equal in a theoretical RC circuit?Plase explain your answer by using relating formula.
a. Show how you would connect all five capacitors to get a maximum capacitance and find the maximum capacitance in terms of C. b. Show how you would connect all five capacitors to get a minimum capacitance and find the minimum capacitance in terms of C.
To measure the capacitance C of a capacitor, you attach the capacitor to a battery and wait until it is fully charged. You then disconnect the capacitor from the battery and let it discharge through a resistor of resistance RR. You measure the time T1/2 that it takes the voltage across the resistor to decrease to half its initial value at the instant that the connection to the capacitor is first completed. You repeat this for several different resistors. You plot the data as T1/2 versus R and find that they lie close to a straight line that has slope 9.00 μF. What is the capacitance C of the capacitor?
For the circuit, now keep switch J2 closed, close switch J1. Determine the expressions for the voltage across the capacitor and the current delivered by the source. Find the time it takes for the capacitor to reach its final voltage and what value it is.
Write the equation for the capacitor voltage and current equations and the voltage at the R2 end when the switch K is turned to position 2.
A 10-9.F capacitor (1 nanofarad) is charged to 50 V and then disconnected. One can model the charge leakage of the capacitor with a RC circuit with no voltage source and the resistance of the air between the capacitor plates. On a cold dry day, the resistance of the air gap is 3× 1018 2, on a humid day, the resistance is 6 × 10° 2. How long will it take the capacitor voltage to dissipate to half its original value on each day? ... On the dry day, it will take seconds.
The initial capacitor voltage is 4 V. Switch S1 is closed at t = 0. The charge (in micro C) lost by the capacitor form t = 25 microS to t = 100 microS is:1) 6.992) 8.713) 5.554) 10Please show detailed steps and work
how do i calculate the inverse capacitance and its uncertainty if the capacitance value 1.8748+/- 0.0006. please show steps im using this example to do my other values.
Please help will upvote for sureFor the circuit below:a) What is the maximum current at any time in the circuit?b) Write Equation of capacitor voltage in any time and find the capacitor voltage at t=1msec, t=10msec, t=1sec and t=10sec?d) Draw the capacitor voltage and current signal versus time axis and sign four different time values in (c) on it?
Suppose that we have a 1000-pF parallel-plate capacitor with air dielectric charged to 1000 V. The capacitor terminals are open circuited. Find the stored energy. If the plates are moved farther apart so that d is doubled, determine the new voltage on the capacitor and the new stored energy. Where did the extra energy come from?
A parallel plate capacitor has an electrode area of 100 mm2 , with spacing of 0.1 mm between the electrodes. The dielectric between the plates is air with a permittivity of 8.85*10-12 F/m. The voltage on the capacitor is 100 V. The stored energy in the capacitor is ?
Please draw the problem and answer, thank you. A capacitor is made of 2 rectangular metal plates with side length of 3 cm x 6 cm separated by a distance of 2.36 cm with water in between the plates. The capacitor has a voltage of 110 v and is not connected to a battery. Calculate the capacitance. What is the new capacitance if we replace water with a new dielectric material with a constant of 3.75 in between the plates? What is the new voltage? What is the charge on each plate?

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