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2. Suppose f (x)= log(tan(1+x)). The following values for f(x) are valid. f(1.00)=-1.456916, ƒ(1.05) =-1.446183, ƒ(1.10)=-1.435709, f(1.15)=-1.42548. %3D -%3D (a) Construct a third degree Lagrange Interpolating polynomial, P,(x) using the given data. (b) Approximate f (1.07). O Determine the following absolute error: | P,(1.13) – ƒ(1.13)|.

2. Suppose f (x)= log(tan(1+x)). The following values for f(x) are valid. f(1.00)=-1.456916, ƒ(1.05) =-1.446183, ƒ(1.10)=-1.435709, f(1.15)=-1.42548. %3D -%3D (a) Construct a third degree Lagrange Interpolating polynomial, P,(x) using the given data. (b) Approximate f (1.07). O Determine the following absolute error: | P,(1.13) – ƒ(1.13)|.

Advanced Engineering Mathematics
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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May you please answer letters a - c. Thank you! 

2. Suppose f (x)= log(tan(1+x)). The following values for f(x) are valid. f(1.00)=-1.456916, ƒ(1.05) =-1.446183, ƒ(1.10)=-1.435709, f(1.15)=-1.42548. %3D -%3D (a) Construct a third degree Lagrange Interpolating polynomial, P,(x) using the given data. (b) Approximate f (1.07). O Determine the following absolute error: | P,(1.13) – ƒ(1.13)|.
Transcribed Image Text:2. Suppose f (x)= log(tan(1+x)). The following values for f(x) are valid. f(1.00)=-1.456916, ƒ(1.05) =-1.446183, ƒ(1.10)=-1.435709, f(1.15)=-1.42548. %3D -%3D (a) Construct a third degree Lagrange Interpolating polynomial, P,(x) using the given data. (b) Approximate f (1.07). O Determine the following absolute error: | P,(1.13) – ƒ(1.13)|.
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