2. Prove that the simple random sampling without replacement is more efficient than simple random sampling with replacement.

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1. Assume there are a population size N = 6 with units (2,4,6,8, 10, 12), and out of which
sample size n = 5 units are to be selected based on simple random sampling without
replacement.
a. Prove that the mean of the sample is unbiased estimator for the population mean.
b. Find the mean and variance of the random variable Y = (*/) + 10, where
si = (x;-1)² is unbiased estimator of the variance of the random sample X
22-1
to the population variance, and X is the population mean.
2. Prove that the simple random sampling without replacement is more efficient than simple
random sampling with replacement.
Transcribed Image Text:1. Assume there are a population size N = 6 with units (2,4,6,8, 10, 12), and out of which sample size n = 5 units are to be selected based on simple random sampling without replacement. a. Prove that the mean of the sample is unbiased estimator for the population mean. b. Find the mean and variance of the random variable Y = (*/) + 10, where si = (x;-1)² is unbiased estimator of the variance of the random sample X 22-1 to the population variance, and X is the population mean. 2. Prove that the simple random sampling without replacement is more efficient than simple random sampling with replacement.
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