2. In the reading "Descartes La Geometrie Analytic Geom.pdf" (pages 13-14), Descartes shows how to find solutions to z² = az +b² and z² = −az +b² geometrically. Note that ANLM is a right triangle. a. Show that OM is a solution to z² = az +b². b. Show that PM is a solution to z² = −az+b². 0 N a/2 P b L M

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