If ƒ (x, y) = log (x² + y²), then f +f, is equal to XX yy 1 (a) x² + y² (b) 0 2 1,² - x² (c) (d) (x² + y²)² x² - y² (x² + y²) ²

Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter5: Inverse, Exponential, And Logarithmic Functions
Section: Chapter Questions
Problem 52RE
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2. Iff(x, y) = log (x² + y²), then fu + f is equal to
1
(a)
+ y²
(b) 0
2-²
2-x²
(d)
(x+y=²
(x2+y2²
(c)
x
Transcribed Image Text:2. Iff(x, y) = log (x² + y²), then fu + f is equal to 1 (a) + y² (b) 0 2-² 2-x² (d) (x+y=² (x2+y2² (c) x
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