2. Given the information of the network shown below: L = 0.153 H, C = 0.3183 mF, 1, = 5 L 60°A,and V, = 250 4 90° v.Z312Z2Vs, 50 Hz(a) When Zz is not connected, find:1. Zz and its components2. Vg in the form of Vy sin(wt + 0)3. Power in the circuit(b) Now calculate Z, with its components so that overall power factor of the circuit is unity.

NOTE: Since you have posted a question with multiple subparts, we will solve the first three…

2. Given the information of the network shown below: L = 0.153 H, C = 0.3183 mF, 1, = 52 60°A, and V, = 250 2 90° v. Z3 Z2 Vs, 50 Hz (a) When Zz is not connected, find: 1. Zz and its components 2. Vs in the form of VM sin(wt + 0) 3. Power in the circuit

2. Given the information of the network shown below: L = 0.153 H, C = 0.3183 mF, 1, = 52 60°A, and V, = 250 2 90° v. Z3 Z2 Vs, 50 Hz (a) When Zz is not connected, find: 1. Zz and its components 2. Vs in the form of VM sin(wt + 0) 3. Power in the circuit

Power System Analysis and Design (MindTap Course List)

6th Edition

ISBN:9781305632134

Author:J. Duncan Glover, Thomas Overbye, Mulukutla S. Sarma

Publisher:J. Duncan Glover, Thomas Overbye, Mulukutla S. Sarma

Chapter6: Power Flows

Section: Chapter Questions

Problem 6.61P

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Concept explainers

Current Division Method

The generalized current divider formula is given by the following relation below,

Question

2. Given the information of the network shown below: L = 0.153 H, C = 0.3183 mF, 1, = 5 L 60°A,
and V, = 250 4 90° v.
Z3
12
Z2
Vs, 50 Hz
(a) When Zz is not connected, find:
1. Zz and its components
2. Vg in the form of Vy sin(wt + 0)
3. Power in the circuit
(b) Now calculate Z, with its components so that overall power factor of the circuit is unity.

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