2. Given fy 60000 psi, fé= 4000 psi, fr = 474.3 psi, Mer 1.295 x 106 lb in, and beam weight is included in the dead load shown, complete parts (a) and (b). Assume normal weight concrete. There is an additional live load of 2.5 k/ft acting across the length of the beam as well. The cracking moment of inertia for the section is 27,225 in² and Ec = 57000√f. ACI 24.2.3.5 is shown below, along with the maximum deflection of a cantilever w1² under a uniformly distributed load. Maximum moment under this load is a. Compute the effective moment of inertia. b. Compute the instantaneous deflection of the beam. = Ma≤(2/3)Mer WD = 2 k/ft Ma> (2/3)Mar 18 ft Ma 24.2.3.5 For nonprestressed members, unless obtained by a more comprehensive analysis, effective moment of inertia, I shall be calculated in accordance with Table 24.2.3.5 using: = 1- frIg Y₁ Table 24.2.3.5-Effective moment of inertia, I Service moment Effective moment of inertia, Is in.4 Ig I 6 #11 4)(1-4) 16 in. (2/3)Mer M 4 in. 27 /in. (24.2.3.5) 32 in. (a) (b) = w k/ft Sfree end = we SEI

Structural Analysis
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ISBN:9781337630931
Author:KASSIMALI, Aslam.
Publisher:KASSIMALI, Aslam.
Chapter2: Loads On Structures
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This is civil engineering concrete design practice. Everything needed is provided. Please answer all parts to the best of your ability. Provide thorough answer and explanation. This is only one question with a max of 2 parts due to guidelines.

2. Given fy
60000 psi, f = 4000 psi, fr = 474.3 psi, Mer
1.295 x 106 lb in, and beam weight is included
in the dead load shown, complete parts (a) and (b). Assume normal weight concrete. There is an additional live
load of 2.5 k/ft acting across the length of the beam as well. The cracking moment of inertia for the section is
27,225 in and Ec = 57000√f. ACI 24.2.3.5 is shown below, along with the maximum deflection of a cantilever
w1²
under a uniformly distributed load. Maximum moment under this load is
a. Compute the effective moment of inertia.
b. Compute the instantaneous deflection of the beam.
=
Ma≤(2/3)Mer
WD = 2 k/ft
Ma> (2/3)Mer
18 ft
Ma
24.2.3.5 For nonprestressed members, unless obtained by a
more comprehensive analysis, effective moment of inertia, I
shall be calculated in accordance with Table 24.2.3.5 using:
=
1-
frIg
Y₁
Table 24.2.3.5-Effective moment of inertia, I,
Service moment
Effective moment of inertia, Ie, in.4
Ig
I
6 #11
4)(1-4)
16 in.
(2/3)Mer
M₁
4 in.
27-in.
(24.2.3.5)
32 in.
(a)
(b)
=
w k/ft
Sfree end =
we
SEI
Transcribed Image Text:2. Given fy 60000 psi, f = 4000 psi, fr = 474.3 psi, Mer 1.295 x 106 lb in, and beam weight is included in the dead load shown, complete parts (a) and (b). Assume normal weight concrete. There is an additional live load of 2.5 k/ft acting across the length of the beam as well. The cracking moment of inertia for the section is 27,225 in and Ec = 57000√f. ACI 24.2.3.5 is shown below, along with the maximum deflection of a cantilever w1² under a uniformly distributed load. Maximum moment under this load is a. Compute the effective moment of inertia. b. Compute the instantaneous deflection of the beam. = Ma≤(2/3)Mer WD = 2 k/ft Ma> (2/3)Mer 18 ft Ma 24.2.3.5 For nonprestressed members, unless obtained by a more comprehensive analysis, effective moment of inertia, I shall be calculated in accordance with Table 24.2.3.5 using: = 1- frIg Y₁ Table 24.2.3.5-Effective moment of inertia, I, Service moment Effective moment of inertia, Ie, in.4 Ig I 6 #11 4)(1-4) 16 in. (2/3)Mer M₁ 4 in. 27-in. (24.2.3.5) 32 in. (a) (b) = w k/ft Sfree end = we SEI
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