2. For the circuit below perform the following analysis. a. Use Source Transformation Techniques to simplify the part of the circuit to the left of the 2.5kn resistor as much as possible. b. Determine the voltage drop V across the 2.5k2 resistor 6.7ka 1.5kn 8.3kQ 2.5ka -24V

Work out vbout and vcout

For the circuit shown in the figure select the best value forces voltage V

For given value of the circuit, Vsupply = 120 V, and with R₁= 2002, R₂=30.0N, R3=75N, R4=30N, R5= 2002, R6-400 and R7=12002? What is the current flow in resistor R4? 1.2 Amp. 1.0 Amp. 0.67 Amp. 2 Amp. V1 -120 V R1 m 2002 R3 750 R7 12002 R6 4002 R2 2300 R4 3002 R5 200

6 cells with 2 V emf and 0.1ohm internal resistance are connected in series. Four such sets are connected in parallel. The entire circuit is connected to a 9.85 ohm load. So find the load current, the current through each cell and the load voltage.

Determine the current Is in the following circuit. V = 130V, R₁ = 9900, R₂ = 22002, R3 = 32000, R4 = 55000, R5 = 1000, R6 = 130, R7 = 990, and Rg = 1450. R5 R1 R2 ww ww R3 Is + www V R7 ми R4 R6 R8 ww ww ww

- Find Equivalent resistance of the circuit - Find the current through R5 - Find the voltage drop across R5 - Find the voltage drop across R4

A resistor and capacitor are connected in parallel to a 277-V, 60-Hz power source. The resisitor has a value of 50Ω and the capacitor has a value of 40uF. What is the circuit power factor? Show your work.

The voltage divider rule states that  Select one: a. the voltage applied to a parallel resistīve circuit will be dropped across all resistors in proportion to the magnitude of the individual resistors  b. the voltage applied to a serles resistive circuit will be dropped across all resistors in proportion to the magnitude of the individual resistors c. the current passing to a series resistive circuit will be dropped across all resistors in proportion to the magnitude of the Individual resistors  d. None of the answers

Q.2/ Given the information as shown n the figure Vcc 1-Ic 2- Vcc 3 - B 4- RB 2.2 k2 RB VCE=7.2 V IB=20MA IE= 4 mA