2. Find the current i,, iz and iz in the circuit below: 1852 35

What impedance vector - j25 represents:A. A pure resistance.            C. A pure capacitance.B. A pure inductance.           D. An inductance combined with a resistance.

Problem 5 Find the equivalent inductance Leg for the network shown below. 72 mH oooo Leg 49 mH elle elle 313 mH elle 64 mH elle 80 mH

Please disregard the question on the picture. Here's the right question, at what frequency will the value of the impedance be twice that at 25Hz (refer to the given in question #20).

What impedance vector (0- j15) Ohms represents:A. A pure resistance.         C. A pure capacitance.B. A pure inductance.       D. An inductance combined with a capacitance.

The circuit shown in figure EM1-1 shows an AC voltage source VAC connected in series with a load that has • resistance R=280 Ohms, inductance L=1.1mH, and • capacitance C=4.7mF. Calculate values of, and select the apporpriate answer from the list from the list below for • the frequency, fres (in Hz) of the AC source that results in resonance in the load and the impedance, Zres (in Ohms) of the load at this frequency. ● Resonant Frequency, fres= ✓ Hz Impedance of the Load at Resonance, Zres= R 280 Ω ✓ Ohms V. AC L 4.7 mF 1.1 mH Figure EM1-1 Downloadable image

The current through a 15kohm resistor is given below, using Ohm’s Law to find the voltage, convert to polar form, complete the math, then convert back to the waveform at i1 = 3.5sin(2500t) mA and i2 = 2.3sin(200t – 60°) mA

Ac - 100 VrmsR1 - 1kR2 - 500Rload - 1kCapacitor - 2uF Q1. How much is the capacitor voltage lagging from the AC source

A pure resistance of 50 ohms is in series with a pure capacitance of 100 microfarads. The series combination is connected across a 100 volt, 50 hz source. Find the a) impedance, b) phase angle, and c) equation of the current

Ministry of Manpower Directorate General of Technological Education Salalah College of Technology Zlectrical Inginearina Problem - 8 Refer to the circuit below and -25V C2 N. compute the following: i) Total capacitance ii) Voltage across C, iii)Charge across C, iv)Voltage across C5 5 uF C1 5 uF 5 uF C4 5 uF C6 5 uF -16-65V. C5 5 uF (Take V, as 25V) 8-35V VT 25V