2. FIND THE (1) TOTAL VOLTAGE, (2) TOTAL RESISTANCE, (3) CURRENT IN R1, (4) CURRENT IN R2, (5) CURRENT IN R3 AND (6) CURRENT IN R4. THE DIAGRAM BELOW IS A PARALLEL CIRCUIT. JR R2 JR4 Er. 120V GO25822 12052 802
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- Which one or ones of the following statements about Kirchhoff's rules are correct? I) The junction rule is based on the law of conservation of energy. II) The loop rule is based on the law of conservation of energy. III) The number of required equations to find the unknown currents has to be as many as the number of all possible loops. O A) Il and II B) II O C) I and II O D) II O E) ITwo batteries are connected in parallel delivering power to a power resistor. The first battery has an open circuit voltage of 12.6 V and an internal resistance of 0.2 ohm. The second battery has an open circuit voltage of 12.2 V and an internal resistance of 0.3 ohm. Find the maximum power delivered to the load resistance.i) Create the simplified circuit for the ‘A’ segment. ii) In the same work space, create the simplified circuits for the ‘B’ and ‘C’ segments . Note: You are putting all circuit in the same work space because you will need to join all the different parts together at the end. Take a picture or screenshot and include here. iii) Connect the 3 circuits in i) and ii) simultaneously to produce the number 7. You will need to set the inputs W,X,Y,Z to 0, 1, 1, 1 respectively. Take a picture or screenshot of the circuit (with the LED display) and include it here.
- Subject: CircuitsGivenRt = 37.9529 ohm..Rcd = 3.6 ohm.Rab=2.3529ohmIt=1.58APt=94.85WV2=3.16VV4=6.32VVab=3.7175vVcd=5.688VI10=0.372AI5=0.7435AI8=0.465AI9=0.632AI6=0.348AP2=4.9928WP4=9.9856WPab=5.88WP14=34.95WPcd=8.99WP12=29.96WIn a house, a circuit often includes multiple electrical outlets which are parallel-connected to a single voltage source. Each of these circuits also contains a 15-A circuit breaker. Design a parallel-connected circuit which shows three electrical outlets con-nected to a voltage source with a circuit breaker. What is the advantage of having out-lets parallel-connected, and why is a circuit breaker connected in series with the voltage source? Why is the circuit breaker considered a necessary safety item in the circuit?Which of the following statements are correct for the circuit below? Thanks to the capacitors I – C1 and C2, the voltage gain of the circuit increases. II – Capacitors C1 and C2 are coupling capacitors and provide an isolation function between AC and DC voltages in the circuit. Thanks to the III – RE resistor, the voltage gain of the circuit increases. Thanks to the IV – RE resistor, the stability of the circuit increases. The V – C3 Capacitor is a bypass capacitor and prevents the loss of voltage gain. Capacitor VI – C3 is a coupling capacitor and has no effect on the voltage gain in the circuit. VII – As the value of the source internal resistance Rs increases, the voltage gain decreases. VIII – The voltage gain decreases as the value of any RL load to be added to the circuit increases
- Find the loop currents (Ia, Ib, Ic) and the currents passing through each circuit element and the voltages falling on the circuit elements.To measure the change in resistance of the gage(s) and indicate the location of the gauge on the beam, construct the Wheatstone bridge circuit. Calculate the Wheatstone bridge output if the gauge indicates a strain of 4000.then,Evaluate how can the number of strain gauges affects your measurement result. Justify your response with a calculation and a diagram showing the gage's placement on the beam.Determine the total voltage, VT and the resistance, R3 in the circuit shown in Figureif the voltage across R1 is 4v and the current through R4 is 1.5 A.
- A 5-ohm resistance is connected in parallel with a 10- ohm resistance. Another set, a 6-ohm and 8-ohm resistances are also in parallel. The two sets are connected in series. - - - Draw the circuit, find the equivalent resistance, total current, and the voltage across each resistor.What is the zener current for the circuit shown? Please choose one: a. 6.0 mA b. 9.0 mA c. 7.5 mA D. 3.0 mAPlease help me solve for the total resistance, total current, and individual voltage if: VT = 30 VR1 = 7 ohmsR2 = 10 ohmsR3 = 6 ohmsR4 = 4 ohmsR5 = 8 ohmsR6 = 9 ohmsR7 = 5 ohmsR8 = 12 ohmsR9 = 3 ohmsR10 = 8 ohms