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Please just solve abc asap and just send the paper solutions asap please faster and use 9.81 for acceleration not 9.8 and only ise these equation
2. Examine the velocity-time graph in Figure 11. KU O A
Velocity v. Time
40
30
20
10
4
6
t (s)
Figure 11
(a) Determine the average acceleration for the entire trip. [ans: 6 m/s (torward
(b) Determine the instantaneous acceleration at 3 s and at 5 s. [ans: 6 m/s [forward); 10 m/s [forward]
(c) Draw a reasonable acceleration-time graph of the motion.
([pemoj] s/u) A
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Transcribed Image Text:2. Examine the velocity-time graph in Figure 11. KU O A Velocity v. Time 40 30 20 10 4 6 t (s) Figure 11 (a) Determine the average acceleration for the entire trip. [ans: 6 m/s (torward (b) Determine the instantaneous acceleration at 3 s and at 5 s. [ans: 6 m/s [forward); 10 m/s [forward] (c) Draw a reasonable acceleration-time graph of the motion. ([pemoj] s/u) A
SPH4U-01
COHORT A
Wednesday, April 7th, 2021
Equations and Constants
F = µFn
sinA
sinB
sinc
Fnet
= ma
a? = b2 + c2 – 2bccosA
a
C
V2 = V1 + aAt
Ad
Ad = V;At + ½aAt?
Ad = v2At - ½aAt
Vav
Ad = %(v1 + V2)At
(v2)? = (vi)? + 2aAd
v2
a. =
%3D
9 = 9.81
472r
.?זז"ח4 -
T2
W FAd
W= ΔΕ
PE = mgAy
1
KE =
mv2
2.
F = kx
1
Elastic Energy =
kx2
p3mv
FΔt-Δρ
GMm
mearth
5.972 x 1024kg
mmoon = 7.348 x 1022kg
r2
Nm2
G = 6.67x10-11
kg2
Te = 6378 km
Tmoon
= 1737 m
kq192
F. =
= 1.67 x 10-27kg
= 9.11 x 10-31kg
mproton
melectron
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Transcribed Image Text:SPH4U-01 COHORT A Wednesday, April 7th, 2021 Equations and Constants F = µFn sinA sinB sinc Fnet = ma a? = b2 + c2 – 2bccosA a C V2 = V1 + aAt Ad Ad = V;At + ½aAt? Ad = v2At - ½aAt Vav Ad = %(v1 + V2)At (v2)? = (vi)? + 2aAd v2 a. = %3D 9 = 9.81 472r .?זז"ח4 - T2 W FAd W= ΔΕ PE = mgAy 1 KE = mv2 2. F = kx 1 Elastic Energy = kx2 p3mv FΔt-Δρ GMm mearth 5.972 x 1024kg mmoon = 7.348 x 1022kg r2 Nm2 G = 6.67x10-11 kg2 Te = 6378 km Tmoon = 1737 m kq192 F. = = 1.67 x 10-27kg = 9.11 x 10-31kg mproton melectron
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