2. Determine the length of SV when TVL SU and UV = 5.3. T S U OSV = 7.95 SV = 2.65 OSV = 10.6 SV = 5.3 Ro

Elementary Geometry For College Students, 7e
7th Edition
ISBN:9781337614085
Author:Alexander, Daniel C.; Koeberlein, Geralyn M.
Publisher:Alexander, Daniel C.; Koeberlein, Geralyn M.
ChapterP: Preliminary Concepts
SectionP.CT: Test
Problem 1CT
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**Problem 2: Determine the length of SV**

**Given:** TV ⊥ SU and UV = 5.3.

**Diagram Explanation:**
The diagram features a triangle \( \Delta STU \) with a right angle (indicated by a red square) at point V where TV is perpendicular to SU. Point V is located on line SU directly below point T, forming two right-angled triangles: \( \Delta TVU \) and \( \Delta TVS \).

A vertical line \( TV \) drops from point T perpendicularly to line SU intersecting at V. The length of UV is given as 5.3 units.

**Question:** Find the length of \( SV \).

**Possible Answers:**
1. \( SV = 7.95 \)
2. \( SV = 2.65 \)
3. \( SV = 10.6 \)
4. \( SV = 5.3 \)

To solve this problem, use the Pythagorean theorem or other geometric properties of right triangles as needed to determine the correct length of SV.
Transcribed Image Text:**Problem 2: Determine the length of SV** **Given:** TV ⊥ SU and UV = 5.3. **Diagram Explanation:** The diagram features a triangle \( \Delta STU \) with a right angle (indicated by a red square) at point V where TV is perpendicular to SU. Point V is located on line SU directly below point T, forming two right-angled triangles: \( \Delta TVU \) and \( \Delta TVS \). A vertical line \( TV \) drops from point T perpendicularly to line SU intersecting at V. The length of UV is given as 5.3 units. **Question:** Find the length of \( SV \). **Possible Answers:** 1. \( SV = 7.95 \) 2. \( SV = 2.65 \) 3. \( SV = 10.6 \) 4. \( SV = 5.3 \) To solve this problem, use the Pythagorean theorem or other geometric properties of right triangles as needed to determine the correct length of SV.
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