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2. Consider the function Se=1/x f(x) = { 0 x>0 x ≤0. Graph/sketch this function. Show that this function satisfies f(n) (0) 0 for all n ≥ 0 so its Taylor series must be 0+0·x+0·x² + ... = 0. Why is f itself is not equal to its Taylor series? ∞ (1) =

2. Consider the function Se=1/x f(x) = { 0 x>0 x ≤0. Graph/sketch this function. Show that this function satisfies f(n) (0) 0 for all n ≥ 0 so its Taylor series must be 0+0·x+0·x² + ... = 0. Why is f itself is not equal to its Taylor series? ∞ (1) =

Algebra & Trigonometry with Analytic Geometry
Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter2: Equations And Inequalities
Section2.1: Equations
Problem 62E
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2. Consider the function Se=1/x f(x) = { 0 x>0 x ≤0. Graph/sketch this function. Show that this function satisfies f(n) (0) 0 for all n ≥ 0 so its Taylor series must be 0+0·x+0·x² + ... = 0. Why is f itself is not equal to its Taylor series? ∞ (1) =
Transcribed Image Text:2. Consider the function Se=1/x f(x) = { 0 x>0 x ≤0. Graph/sketch this function. Show that this function satisfies f(n) (0) 0 for all n ≥ 0 so its Taylor series must be 0+0·x+0·x² + ... = 0. Why is f itself is not equal to its Taylor series? ∞ (1) =
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