DATA AND RESULTS1. OBSERVED DATAOBSERVED DISTANCE OBSERVED BEARINGLATITUDEDEPARTURELINE(m)(*'")N82° 12' ES 48° 12' E(m)(m)AB229.70+ 31.17+ 227.57BC130.55- 87.02+ 97.32CD161.46S 48° 20' W- 107.34- 120.61EFS 87° 43' W180.49- 7.19- 180.35EA171.83N 07° 59' w+ 170.16- 23.86D= 874.03Ca =0.070.222. ADJUSTED DATA by COMPASS RULEADJUSTEDADJUSTEDADJUSTEDLINELATITUDEDE PARTUREDISTANCE (m)BEARING (*")(m)(m)АВBCCDEFEA3. AREA BY DOUBLE MERIDIAN DISTANCE (DMD)ADJUSTEDADJUSTEDDMDLINELATITUDEDEPARTUREDA (sq. m)(m)(m)(m)ABBCCDEFEAΣDAАтотA B. PROCEDURE1. Establish corners of the designated field and mark these corners as stations A, B, C, D, and E withflaglets.2. Set up and level the Engineer's Transit at station A.3. Unlock the needle lifter of the compass box to enable movement of the compass needle.4. With the telescope in normal position, sight station A then lock the upper and lower clamps toprevent unnecessary movement of the upper plate. When the needle becomes stationary, readthe north end of the needle to determine the bearing of line AB. Record the obtained data in theaccompanying table.- The telescope is in normal position when the eye piece of the telescope is in the south end of the compassneedle or when the eye piece is above vernier A.- In reading bearings, the north end of the needle is the one without the attached copper wire.5. Transfer to the next station and repeat steps b, c, and d for bearings of lines BC, CD, DE, and EA.Record each obtained data in the accompanying table.6. Measure the lengths of lines AB, BC, CD, DE, EA. Record the obtained distances in theaccompanying table.daadedacdnsdeo

Given a closed traverse and it is asked to find adjusted value by compass rule and area by DMD…

2. ADJUSTED DATA by COMPASS RULE ADJUSTED ADJUSTED ADJUSTED LINE LATITUDE DE PARTURE DISTANCE (m) BEARING (* ") (m) (m) AB BC CD EF EA 3. AREA BY DOUBLE MERIDIAN DISTANCE (DMD) ADJUSTED ADJUSTED DMD LINE LATITUDE DA (sq. m) DEPARTURE (m) (m) (m) AB BC CD EF EA ΣDA Атотл

2. ADJUSTED DATA by COMPASS RULE ADJUSTED ADJUSTED ADJUSTED LINE LATITUDE DE PARTURE DISTANCE (m) BEARING (* ") (m) (m) AB BC CD EF EA 3. AREA BY DOUBLE MERIDIAN DISTANCE (DMD) ADJUSTED ADJUSTED DMD LINE LATITUDE DA (sq. m) DEPARTURE (m) (m) (m) AB BC CD EF EA ΣDA Атотл

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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: Work out included angles from following data : Sr. No. Line F.B. AB 40° BC 120° CD 240⁰ DA 340⁰ 160' 1 2 3 4 B.B. 220' 300' 60' 1
Meet - nzw-pimo-rw anuwwlPx-a_a7HdrtDNnmaFDF2GGA/formResponse none of the above. O To establish a new benchmark on point Busing a levelling instrument. The work had been done between B.M1 and B.M2 to the required point B, and the observations were recorded as in the tables below. Calculate the best value *of elevation for point B B.M1 B B.M2 B BS Point B.M1 T. P1 BS FS 3.305 Remarks RL-34.585 FS 0.405 4.24 3.35 Point Remarks B 30.06 0.672 1.825 2.485 3.315 1.23S 3.715 T. P4 T. PS B.M2 1.795 A 4.01 3.485 Т. Р2 T. P3 3.315 2.78 RL=42.093 B 39.97m 41.97m 46.97m 45.98m O 44.37m O 40.95m O * Reciprocal ranging is employed when one end of a line is inaccessible. O the ends of the line are not visible even from intermediate points. O both the ends are inaccessible. the two ends of a line are not intervisible,O O O O O O O O O O OC
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FIND FOR THE CALCULATED BEARINGS, LATITUDE AND DEPARTURE. NEED ALSO TO FIND THE ADJUSTED LATITUDE AND ADJUSTED DEPARTURE. FIND THE DMD AND THE AREA. Sta Dist Occ Qbs (m) Observed Interior Angle Direct Adjusted Interior Angle - 0°19'12"| 102°50'18" Sta Мean Rist Reversed Mean A E 11.55 12.375 103°22" 102°57' 103°09'30" - 13.20 A 13.20 | 15.310 88°14' 88°14' 88°14" - 0°19'12" | 87°54'48" 17.42 В 17.42 13.710 113°36 112°48' 113°12" - 0°19'12" | 112°52'48" 10.00 10.00 11.950 156°06" 154°31' 155°18'30" - 0°19'12"| 154°59'18" E 13.90 E D 13.90 | 12.725 81°42 81°42' 81°42' - 0°19'12"| 81°22'48" A 11.55 AZIMUTH: 296° LINE Length, Calculated LATITUDE DEPARTURE Bearing +N -S +E -W AB 13.20 BC 17.42 CD 10.00 DE 13.90 EA 11.55 = 66.070 LINE ADJUSTED LATITUDE ADJUSTED DEPARTURE DMD DOUBLE +N -S +E -W AREA 2A AB ВС CD DE EA
Given the corrected latitudes and departure of a closed traverse. LINES 1-2 2-3 3-4 4-5 5-6 6-1 LATITUDE +80.16 40.13 +70.18 30.14 +60.20 - 140.27 Find the Area of the lot using a. DMD Method b. DPD Method DEPARTURE 40.12 -36.82 +50.42 +30.36 52.34 +48.50 Note: Using both methods will give same answer
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