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2. A) d f(x) dx g(x) = Circle the correct expression for the quotient rule: B) f'(x)g(x)−f(x)g'(x) == g²(x) d f(x) f(x)g'(x)-f'(x)g(x) dx g(x) g²(x) d f(x) f'(x)g(x)−ƒ(x)g'(x) c). = D) = dx g(x) g(x) d f(x) f'(x)g(x)+f(x)g'(x) dx g(x) g²(x)

2. A) d f(x) dx g(x) = Circle the correct expression for the quotient rule: B) f'(x)g(x)−f(x)g'(x) == g²(x) d f(x) f(x)g'(x)-f'(x)g(x) dx g(x) g²(x) d f(x) f'(x)g(x)−ƒ(x)g'(x) c). = D) = dx g(x) g(x) d f(x) f'(x)g(x)+f(x)g'(x) dx g(x) g²(x)

Calculus: Early Transcendentals
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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2. A) d f(x) dx g(x) = Circle the correct expression for the quotient rule: B) f'(x)g(x)−f(x)g'(x) == g²(x) d f(x) f(x)g'(x)-f'(x)g(x) dx g(x) g²(x) d f(x) f'(x)g(x)−ƒ(x)g'(x) c). = D) = dx g(x) g(x) d f(x) f'(x)g(x)+f(x)g'(x) dx g(x) g²(x)
Transcribed Image Text:2. A) d f(x) dx g(x) = Circle the correct expression for the quotient rule: B) f'(x)g(x)−f(x)g'(x) == g²(x) d f(x) f(x)g'(x)-f'(x)g(x) dx g(x) g²(x) d f(x) f'(x)g(x)−ƒ(x)g'(x) c). = D) = dx g(x) g(x) d f(x) f'(x)g(x)+f(x)g'(x) dx g(x) g²(x)
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