2. A belt is transferring charge to the high-potential inner shell of a Van de Graaff accelerator at the rate of 2.83 x 10-C/s. If the width of the belt carrying the charge is 50cm and the belt travels at a speed of 30 m/s[See Figure 2). (a) The statement of the problem implies that current is I = 2.83 x 10-3C/s. (True,False) (b) Assuming (a) is correct then the surface charge density on the belt follows as K 2.83 x 10-3C/s = 1.89 x 10-4C/m² (True, False) %3D %3D (0.5m)(30m/s)

College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
icon
Related questions
Question
**Figure 2 Explanation:**
The diagram illustrates a configuration involving wires and a sheet of charge. The notation \( N i = I \) indicates a relationship between the number of wires (\( N \)), current per wire (\( i \)), and total current (\( I \)).

- **Wires Carrying Current:** Represented with circular symbols having dots, signifying current flowing out of the page.
- **Sheet of Charge:** Represented as a vertical rectangle moving downward, characterized by its width \( w \) and velocity \( v \).

The equation \( N i = I = K w \) and \( K = \sigma v \) denotes:
- \( K \) as the surface current density with the unit of A/m (amperes per meter).
- \( \sigma \) as the surface charge density.

**Problem Context:**
1. **Charge Transfer:** A belt transfers charge to a Van de Graaff accelerator's high-potential inner shell at \( 2.83 \times 10^{-3} \, \text{C/s} \).
2. **Belt Specifications:** Width of the belt is 50 cm, and it travels at 30 m/s.

(a) **Current Verification:**
- The problem states the current \( I \) as \( 2.83 \times 10^{-3} \, \text{C/s} \). Evaluation needed: True, False.

(b) **Surface Charge Density Calculation:**
- Expression: 
  \[
  \sigma = \frac{K}{v} = \frac{L}{w \, v} = \frac{I}{w v} = \frac{2.83 \times 10^{-3} \, \text{C/s}}{(0.5 \, \text{m})(30 \, \text{m/s})} = 1.89 \times 10^{-4} \, \text{C/m}^2
  \]
- Evaluation needed: True, False.

This information provides an in-depth understanding of the charge dynamics and mathematical verification for a belt-driven charge transfer system as seen in devices like Van de Graaff accelerators.
Transcribed Image Text:**Figure 2 Explanation:** The diagram illustrates a configuration involving wires and a sheet of charge. The notation \( N i = I \) indicates a relationship between the number of wires (\( N \)), current per wire (\( i \)), and total current (\( I \)). - **Wires Carrying Current:** Represented with circular symbols having dots, signifying current flowing out of the page. - **Sheet of Charge:** Represented as a vertical rectangle moving downward, characterized by its width \( w \) and velocity \( v \). The equation \( N i = I = K w \) and \( K = \sigma v \) denotes: - \( K \) as the surface current density with the unit of A/m (amperes per meter). - \( \sigma \) as the surface charge density. **Problem Context:** 1. **Charge Transfer:** A belt transfers charge to a Van de Graaff accelerator's high-potential inner shell at \( 2.83 \times 10^{-3} \, \text{C/s} \). 2. **Belt Specifications:** Width of the belt is 50 cm, and it travels at 30 m/s. (a) **Current Verification:** - The problem states the current \( I \) as \( 2.83 \times 10^{-3} \, \text{C/s} \). Evaluation needed: True, False. (b) **Surface Charge Density Calculation:** - Expression: \[ \sigma = \frac{K}{v} = \frac{L}{w \, v} = \frac{I}{w v} = \frac{2.83 \times 10^{-3} \, \text{C/s}}{(0.5 \, \text{m})(30 \, \text{m/s})} = 1.89 \times 10^{-4} \, \text{C/m}^2 \] - Evaluation needed: True, False. This information provides an in-depth understanding of the charge dynamics and mathematical verification for a belt-driven charge transfer system as seen in devices like Van de Graaff accelerators.
Expert Solution
trending now

Trending now

This is a popular solution!

steps

Step by step

Solved in 4 steps

Blurred answer
Knowledge Booster
Electric field
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, physics and related others by exploring similar questions and additional content below.
Similar questions
Recommended textbooks for you
College Physics
College Physics
Physics
ISBN:
9781305952300
Author:
Raymond A. Serway, Chris Vuille
Publisher:
Cengage Learning
University Physics (14th Edition)
University Physics (14th Edition)
Physics
ISBN:
9780133969290
Author:
Hugh D. Young, Roger A. Freedman
Publisher:
PEARSON
Introduction To Quantum Mechanics
Introduction To Quantum Mechanics
Physics
ISBN:
9781107189638
Author:
Griffiths, David J., Schroeter, Darrell F.
Publisher:
Cambridge University Press
Physics for Scientists and Engineers
Physics for Scientists and Engineers
Physics
ISBN:
9781337553278
Author:
Raymond A. Serway, John W. Jewett
Publisher:
Cengage Learning
Lecture- Tutorials for Introductory Astronomy
Lecture- Tutorials for Introductory Astronomy
Physics
ISBN:
9780321820464
Author:
Edward E. Prather, Tim P. Slater, Jeff P. Adams, Gina Brissenden
Publisher:
Addison-Wesley
College Physics: A Strategic Approach (4th Editio…
College Physics: A Strategic Approach (4th Editio…
Physics
ISBN:
9780134609034
Author:
Randall D. Knight (Professor Emeritus), Brian Jones, Stuart Field
Publisher:
PEARSON