2. (a) A ray of light in air is incident on an air-to-glass boundary at an angle of exactly 30° with the normal. Ifthe index of refraction of the glass is 1.65, what is the angle of the refracted ray within the glass with respect tothe normal? 1. In an experiment to discover the effect of centripetal force on velocity, an object of mass m was swung onthe end of a string in a horizontal circular path of radius r.F = mv²ir [Equation 1]F = mv/rThe string tension provided the centripetal force Fthat produced the centripetal acceleration and kept theobject revolving in its circular path.The centripetal force was determined by using a spring scale or force sensor that measured the tension on thestring.By timing the revolutions and calculating the distance traveled by the object, the velocity v of the object wasdetermined.

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2. (a) A ray of light in air is incident on an air-to-glass boundary at an angle of exactly 30° with the normal. If the index of refraction of the glass is 1.65, what is the angle of the refracted ray within the glass with respect to the normal?

2. (a) A ray of light in air is incident on an air-to-glass boundary at an angle of exactly 30° with the normal. If the index of refraction of the glass is 1.65, what is the angle of the refracted ray within the glass with respect to the normal?

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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Question

2. (a) A ray of light in air is incident on an air-to-glass boundary at an angle of exactly 30° with the normal. If
the index of refraction of the glass is 1.65, what is the angle of the refracted ray within the glass with respect to
the normal?

1. In an experiment to discover the effect of centripetal force on velocity, an object of mass m was swung on
the end of a string in a horizontal circular path of radius r.
F = mv²ir [Equation 1]
F = mv/r
The string tension provided the centripetal force Fthat produced the centripetal acceleration and kept the
object revolving in its circular path.
The centripetal force was determined by using a spring scale or force sensor that measured the tension on the
string.
By timing the revolutions and calculating the distance traveled by the object, the velocity v of the object was
determined.

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