2. 25.00-mL aliquots of the solution in problem 1 are titrated with EDTA to the calmagite end point. A blank containing a small measured amount of Mg²+ requires 2.12 mL of the EDTA to reach the end point. An aliquot to which the same amount of Mg2+ is added requires 25.88 mL of the EDTA to reach the end point. How many mL of EDTA are needed to titrate the Ca2+ ion in the aliquot? а. mL b. How many moles of EDTA are there in the volume obtained in a.? - mol c. What is the molarity of the EDTA solution? - M

Q: If in procedure B analysis of Zn2+ alone, 8.55 mL of 0.0100 M EDTA solution is used to fully titrate…

A: Given: Volume of EDTA =8.55 mL Concentration of EDTA = 0.0100 M To determine: i) mmol of Zn2+

Q: 2. In the pH metric titration of strong and weak acid mixture against strong alkali, generally first…

A: question based on pH metric titraton

Q: A 50.00 ml aliquot of a solution containing Ca2+ and Mg2+ was buffered at pH 10 and titrated with…

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Q: In order to adjust the EDTA solution, 10 mL of 0.01M Ca + 2 sample was taken and 10 mL of pH 10…

A: Ca2+ ions forms a complex compound with EDTA ligand. One mole of Ca2+ inos form complex with one…

Q: um permang

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Q: A 47.00 ml aliquot from a 0.490 L solution that contains 0.410 g of MnSO, (MW = 151.00 g/mol)…

A:

Q: A 15.00 mL urine specimen containing Ca2+ and Mg2+ was diluted to 2.000 L. A 10.00 mL sample was…

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Q: The concentration of CA2+ in an unknown solution was determined by titration with the EDTA solution…

A: Molarity of EDTA solution = 0.000085 M Volume of EDTA solution = 35.54 mL Volume of the diluted…

Q: Find the concentration of 50.0 ml of an acidified Fe2+ solution if 18.72ml of 0.01500M solution of…

A: According to the mole concept, in terms of mass, the amount of substance in moles is equal to the…

Q: A 49.10 mL aliquot from a 0.500 L solution that contains 0.530 g of MnSO4 (MW=151.00 g/mol) required…

A: Solution -

Q: Volhard method. A total of 50.00 ml of 0.1048M AgNO3 is added to the sample and 15.38 ml of 0.3116 M…

A: Given that -  Mass of Chloride containing sample = 10.6 gram  Volume of AgNO3 = 50.00 mL…

Q: titration of 50.00 mL of 0.1100 M Fe3+ with 0.07750 M Sn2+ is carried out. The analytical reaction…

A:

Q: The titration of Zn+2 and EDTA is carried out in the same manner as the Mg+2-EDTA titration. In this…

A: It is explained as given below :

Q: A 100.0 mL100.0 mL solution of 0.0200 M Fe3+0.0200 M Fe3+ in 1 M HClO41 M HClO4 is titrated with…

A: The Nernst equation is shown below: Where; Ecell = electrode potential at any condition E0cell =…

Q: An unknown Ca solution was prepared by weighing a 2.122 g sample, dissolving it in HCl and then…

A:

Q: a 20 mL of EDTA titrant is required to titrate 40 mL of standard 0,25M CaCO3. A 70 mL hard water…

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Q: Calculate the volume at equivalence point and subsequently the pAg when 35.5 mL of 0.125 M I' is…

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Q: How much 0.0500 M EDTA is needed to titrate the Mg and Ca in a 0.2385-g sample that is 92.5%…

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Q: In the titration of 25.00 mL of a water sample, it took 20.690 mL of 4.050x 10−3 M EDTA solution to…

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Q: the MOST appropriate glassware to be used in transferring a 1.000 M Na2CO3 primary standard solution…

A: Proper glassware should be used in the lab to ensure that there are no spills and loss of reagents…

Q: In order to adjust the Potassium Permanganate solution, 0.0544g Na2C2O4 was taken and necessary…

A:

Q: 20. Assume you are using 0.1 M EDTA to titrate a 0.2 M Ca* solution (25 mL) at pH 10.0. V molarity…

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Q: A 1.000 mL aliquot of a solution containing Cu²+ and Ni²+ is treated with 25.00 mL of a 0.03703 M…

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Q: After solubilization, 150 mg of a silver sample is titrated with 25 mL of a solution containing 48.5…

A: Introduction: Molarity is often used to express the concentration of the solution. It is defined as…

Q: Titration of 0.2121 g of primary standard Na C,0, (133.999 g/mol) required 21.66 mL of KMnO,…

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Q: pH 10 buffer

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Q: A 1.000 mL aliquot of a solution containing Cu²+ and Ni²+ is treated with 25.00 mL of a 0.03703 M…

A: Given,Concentration of EDTA = 0.03703 M

Q: 4.50 mL of 0.1 M Ca2+ ion was titrated at pH 10 with 0.1 M EDTA. What will be the concentration of…

A:

Q: 47.6 mL aliquot from a 0.5 L solution that contains 0.45g of MnSO4 (MW is 151 g/mol) required 41.9…

A:

Q: A 1.000 mL aliquot of a solution containing Cu²+ and Ni2+ is treated with 25.00 mL of a 0.03992 M…

A: Given, Concentration of EDTA = 0.03992 M

Q: 50.00 mL of a solution containing both Ni2* and Pb²+ ions requires 46.32 ml of a 0.02041 M EDTA…

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Q: In complexation volumetry, classify the statements below as true or false. Justify the one(s) that…

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Q: Titration of 0.2121 g of primary standard NagC;0, Calculate the molar concentration of KMnO,? 2…

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Q: The titration curve for the titration of a mixture of KI and KCl with AgNO3 is shown. Identify each…

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Q: You titrate 50.00 mL of hard water with 14.86 mL of 0.0100 M EDTA solution. How many moles of Ca²+…

A:

Q: Sample of calcium was buffered to pH 10 prior to analysis. A 25 mL urine sample required 17.25 ml of…

A: The analysis of calcium and magnesium in the urine sanple is done using complexometric titration…

Q: Calculate the volume of 0.0602 M EDTA needed to titrate 11.63 mL of 0.0725 M Mg(NO3)2.

A:

Q: A 47.90 mL aliquot from a 0.500 L solution that contains 0.480 g of MnSO4 (MW= 151.00 g/mol)…

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Q: Using the graph given, which metal can be titrated better with EDTA? A)Fe3+ B) Fe2+ C) Ca2+ D) Hg2+

A: From the graph ,it is clear that Fe 3+ has highest complex formation constant .

Q: 50 mL of a sample known to contain Mg+2 was taken and titrated with 0.075 M EDTA standard solution…

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Q: Construct a titration curve (pCl^- vs. Vtitrant) for the titration of 25.0 mL of 0.100 M Cl^–…

A: Calculation of initial moles of Cl-: n=Molarity×Volume=0.100 mol/L×25.0×10-3 L=0.0025 mol Case 1:…

Q: A 1.000 mL aliquot of a solution containing Cu²+ and Ni²+ is treated with 25.00 mL of a 0.03169 M…

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