2) Write the following code segment in MARIE's assembly language. If X >= Y then X = X* 2 else Y = X - Y + Z;

4) Write the following code segment in MARIE assembly language using given set of variables (symbols). Sum = 0; X = 3; Sum = Sum + X; X = X + 1; Assembly program: Load X Add Store X Load X Loop, Endloop, While X <= 10 do Sum, X, One, Ten, One Load Sum Output Halt Dec Dec Dec Dec 0 3 1 10

Convert the following program into pep/9 assembly language   #include <iostream>using namespace std;int total;int main(){  int num1;int num2;cin >> num1 >> num2;  total = num1 + num2;cout << "Sum = " << total << endl;  return 0;}

Example: The Problem Input File Using C programming language write a program that simulates a variant of the Tiny Machine Architecture. In this implementation memory (RAM) is split into Instruction Memory (IM) and Data Memory (DM). Your code must implement the basic instruction set architecture (ISA) of the Tiny Machine Architecture: //IN 5 //OUT 7 //STORE O //IN 5 //OUT 7 //STORE 1 //LOAD O //SUB 1 55 67 30 55 67 1 LOAD 2- ADD 3> STORE 4> SUB 5> IN 6> OUT 7> END 8> JMP 9> SKIPZ 31 10 41 30 //STORE O 67 //OUT 7 11 /LOAD 1 //OUT 7 //END 67 70 Output Specifications Each piece of the architecture must be accurately represented in your code (Instruction Register, Program Counter, Memory Address Registers, Instruction Memory, Data Memory, Memory Data Registers, and Accumulator). Data Memory will be represented by an integer array. Your Program Counter will begin pointing to the first instruction of the program. Your simulator should provide output according to the input file. Along with…

PLEASE DON'T USE STRUCTS Using C programming language write a program that simulates a variant of the Tiny Harvard Architecture. In this implementation memory (RAM) is split into Instruction Memory (IM) and Data Memory (DM). Your code must implement the basic instruction set architecture (ISA) of the TinyMachine Architecture: 1 -> LOAD 2->ADD 3->STORE 4 -> SUB 5 ->IN 6-> OUT 7-> END 8 -> JMP 9 -> SKIPZ Each piece of the architecture must be accurately represented in your code (Instruction Register, Program Counter, Instruction Memory (IM), MAR1, MDR-1(MAR-1 and MDR-1 are connected to the IM). Data Memory, MAR-2, MDR2 (MAR-2 and MDR-2 are connected to the DM), and Accumulator. Instruction Memory will be represented by an integer array and each instruction will use 2 elements of the array(one for OP and the other one for address) Data Memory will be represented by an integer array and each data value uses an element of the DM array. Your Program Counter will begin pointing to the first…

Convert this following C++ code below to easy68k assembly language: int sum = 0; int c =1; for (unsigned short i = 0; i <= 10; i++) { if (c == 1 ) { sum += i; c = 0; } else { c = 1; } }

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