2 Using Complex number approach ONLY, find the voltage drop across the capacitor, where Vs = 100 VZ00; R = 100 2; XL =75 j (2); Xc = -25j (2). B 15 Ī R C L VR tvc tv₂

Determine ZT for the circuit if inductive reactive is 10220 and resistance is 9850. Answer:

Find the equivalent inductance as seen from the terminals shown in the figure.

Please show work

Q.4Determine the current flowing in the capacitor(-j25ohm) and its direction as shown in Figure below. Assume the voltage source to have negligible impedance.

The current through a 50 mH inductor is given below. Use Ohm’s Law to find the voltage. Convert to polar form, find the impedance and complete the math, then convert back to the waveform at i1 = 7.5sin(2500t – 20°) mA and i2 = 5.9sin(200t + 40°) mA

3-10 A0.25-F capacitor has a current waveform i(t) as shown in Figure P3–10. Determine and plot the voltage waveform v(t) as a function of time. The capacitor is initially a and plot the voltage waveform v(t) as a function of time. The capacitor is imu uncharged. FIGURE P3-10 ilt) 4 A 6. -4 A

Q4. Determine the equivalent inductance and equivalent current of the inductive circuit in Figure Q4. If Ls is replaced with a capacitor of 0.55 mF, how would it affect the branch current? The alternating Voltage source has an amplitude of 25 Vm. Vm Sine 55 Hz L1 5 mH L2 5.3 mH rele cele Figure Q4 000 ele L3 6.6 mH L4 8.3 mH cele L5 7.7 mH