Assuming we take several trials where the total mass ?1+?2 is constant, but we redistribute themasses between ?1 and ?2. The equation you derived as your answer to the Problem (2) would apply.(a) Assume that we took these trials and plottedthe difference in the weights,??−??, on the ?-axis and the accelerationon the ?-axis. What would be the theoretical value–that is, in terms of other known quantities –of the slope?(Once again, you can think of this in terms of your equation answer to the previous problem.(b) For the same plot, what would be the theoretical value of the intercept?(c)Now consider if there were another constant force in the equation, such as friction. What would the theoretical value of the interceptbe in this case? (justify) Consider the system of masses at left.(2)Two masses are connected by a light string andhung over a light, frictionless pulley (meaning we++can neglect the masses of the string and pulley, andany friction forces in the equations). We will specifythat the positive x-direction is to the left over thepulley as shown. Thus motion in the positivedirection means that m, drops while m2 rises. (Nowconsider the opposite - what motion in the negativedirection would mean.)m,W,afar%3DTom.jFree body diagrams are also shown for both hanging masses. Usingseparate instances of Newton's 2nd Law for these two masses, derivea single theoretical equation that solves for the acceleration of thesystem in terms of the unknowns and g. Hint: the tension should notbe one of these unknowns.+x:m,W,Consider the setup and the equation you derived in Problem(3)(2). Assuming we take several trials where the total mass m, + m, isconstant, but we redistribute the masses between m, and m,. The equation you derivedas your answer to the Problem (2) would apply.

Such problems involving Newton's Law can be solved with the help of free body diagram. Drawing free…

Answered: (2) Two masses are connected by a light…

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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Assuming we take several trials where the total mass ?1+?2 is constant, but we redistribute themasses between ?1 and ?2. The equation you derived as your answer to the Problem (2) would apply.

(a) Assume that we took these trials and plottedthe difference in the weights,??−??, on the ?-axis and the accelerationon the ?-axis. What would be the theoretical value–that is, in terms of other known quantities –of the slope?(Once again, you can think of this in terms of your equation answer to the previous problem.

(b) For the same plot, what would be the theoretical value of the intercept?

(c)Now consider if there were another constant force in the equation, such as friction. What would the theoretical value of the interceptbe in this case? (justify)

Consider the system of masses at left.
(2)
Two masses are connected by a light string and
hung over a light, frictionless pulley (meaning we
++
can neglect the masses of the string and pulley, and
any friction forces in the equations). We will specify
that the positive x-direction is to the left over the
pulley as shown. Thus motion in the positive
direction means that m, drops while m2 rises. (Now
consider the opposite - what motion in the negative
direction would mean.)
m,
W,
afar
%3D
T
om.j
Free body diagrams are also shown for both hanging masses. Using
separate instances of Newton's 2nd Law for these two masses, derive
a single theoretical equation that solves for the acceleration of the
system in terms of the unknowns and g. Hint: the tension should not
be one of these unknowns.
+x:
m,
W,
Consider the setup and the equation you derived in Problem
(3)
(2). Assuming we take several trials where the total mass m, + m, is
constant, but we redistribute the masses between m, and m,. The equation you derived
as your answer to the Problem (2) would apply.

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