2- The work done by an external force to move a -4.90 μC charge from point a to point b is 6.60×10−4 J .Part AIf the charge was started from rest and had 3.30×10−4 J of kinetic energy when it reached point b, what must be the potential difference between a and b? (Vb−Va =?)

Write a given values of this question. q=4.9μC=4.9×10-6CWork=6.60×10-4JKE=3.30×10-4J

Answered: 2- The work done by an external force…

Physics for Scientists and Engineers, Technology Update (No access codes included)

9th Edition

ISBN:9781305116399

Author:Raymond A. Serway, John W. Jewett

Publisher:Raymond A. Serway, John W. Jewett

Chapter25: Electric Potential

Section: Chapter Questions

Problem 25.65AP: From Gauss's law, the electric field set up by a uniform line of charge is E=(20r)r where r is a...

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Part A

If the charge was started from rest and had 3.30×10⁻⁴ J of kinetic energy when it reached point b, what must be the potential difference between a and b? (V_b−V_a =?)

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