2) The position of a nanoparticle as a function of time is x(t) = -(1.0 m/s²)t² +(1.0 m/s)t + 6 m, where x is measured in meters, t is measured in seconds and t>0. (a) What is the displacement of the particle between t= 0.0 and t = 2.0 seconds? (b) What is the speed of the nanoparticle when t = 2.0 seconds? (c) What is the maximum position of the particle and at what time does it get there? [Answers: (a) -2.0 m, (b) -3 m/s, (c) 6.25m]
2) The position of a nanoparticle as a function of time is x(t) = -(1.0 m/s²)t² +(1.0 m/s)t + 6 m, where x is measured in meters, t is measured in seconds and t>0. (a) What is the displacement of the particle between t= 0.0 and t = 2.0 seconds? (b) What is the speed of the nanoparticle when t = 2.0 seconds? (c) What is the maximum position of the particle and at what time does it get there? [Answers: (a) -2.0 m, (b) -3 m/s, (c) 6.25m]
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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![1) Two beetles run across flat sand, starting at the same point. Beetle 1 runs 0.50 m due east, then 0.80 m at 30° north
of due east. Beetle 2 also makes two runs; the first is 1.6 m at 40° east of due north. What must be the magnitude
and direction of its second run if it is to end up at the new location of beetle 1? Use vector components to solve this
problem. [Answer: 0.84 m at 79° south of due east)
2) The position of a nanoparticle as a function of time is x(t) = -(1.0 m/s²)t² +(1.0 m/s)t + 6 m, where x is measured in
meters, t is measured in seconds and t>0. (a) What is the displacement of the particle between t= 0.0 and t = 2.0
seconds? (b) What is the speed of the nanoparticle when t = 2.0 seconds? (c) What is the maximum position of the
particle and at what time does it get there?
[Answers: (a) -2.0 m, (b) -3 m/s, (c) 6.25m]
3) A bolt is dropped from a bridge under construction, falling 90 m to the valley below the bridge. (a) In how much time
does it take to pass through the last 20% of its fall? What is its speed (b) when it begins that last 20% of its fall, and
(c) when it reaches the valley beneath the bridge? [(a) 0.45 s, (b) 38 m/s, (c) 42 m/s]
4) A boy throws a rock with an initial velocity of 2.15 m/s at 30.0° above the horizontal. If air resistance is negligible...
a) how long does it take for the rock to reach the maximum height of its trajectory? b)How far from the boy does the
rock land? c) What is the velocity of the rock just before it hits the ground? (0.110s, 0.408m, 2.15m/s @-30.0°)](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F74e06358-63c5-4222-8864-981a923ec3f1%2Fe30616ac-8481-4f18-be88-02caf2ee4748%2Ffroekz5_processed.jpeg&w=3840&q=75)
Transcribed Image Text:1) Two beetles run across flat sand, starting at the same point. Beetle 1 runs 0.50 m due east, then 0.80 m at 30° north
of due east. Beetle 2 also makes two runs; the first is 1.6 m at 40° east of due north. What must be the magnitude
and direction of its second run if it is to end up at the new location of beetle 1? Use vector components to solve this
problem. [Answer: 0.84 m at 79° south of due east)
2) The position of a nanoparticle as a function of time is x(t) = -(1.0 m/s²)t² +(1.0 m/s)t + 6 m, where x is measured in
meters, t is measured in seconds and t>0. (a) What is the displacement of the particle between t= 0.0 and t = 2.0
seconds? (b) What is the speed of the nanoparticle when t = 2.0 seconds? (c) What is the maximum position of the
particle and at what time does it get there?
[Answers: (a) -2.0 m, (b) -3 m/s, (c) 6.25m]
3) A bolt is dropped from a bridge under construction, falling 90 m to the valley below the bridge. (a) In how much time
does it take to pass through the last 20% of its fall? What is its speed (b) when it begins that last 20% of its fall, and
(c) when it reaches the valley beneath the bridge? [(a) 0.45 s, (b) 38 m/s, (c) 42 m/s]
4) A boy throws a rock with an initial velocity of 2.15 m/s at 30.0° above the horizontal. If air resistance is negligible...
a) how long does it take for the rock to reach the maximum height of its trajectory? b)How far from the boy does the
rock land? c) What is the velocity of the rock just before it hits the ground? (0.110s, 0.408m, 2.15m/s @-30.0°)
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