2 kN 4 kN - 250 mm 250 mm -300 mm 20 mm 70 mm 20 mm 50 mm

Q: P

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Q: For the diagram shown, if the load P = 14 kips, determine: a. the normal force in the member Bar BD…

A: Given data: the applied loadP=14 kipsthe diameter of the pin Bd=0.5 intotal length of the beamL=10…

Q: Q2/ Segments AB and BC of the assembly below are made from 6061-T6 aluminum. If a couple forces P= 5…

A: ∑Mx=0Ta+Tc-3X5=0                           (1) COMPATABILITY,…

Q: Horizontal plates are connected to the bar AB whose length varies linearly from zero to HA, as…

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Q: The way to the column where the loading status is seen determine the P load required for the 5 mm…

A: Given that,

Q: Determine the diameter of rivet for the eccentrically loaded riveted joint if the permissible shear…

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Q: For the connection shown, the average shear stress in the 14-mm-diameter bolts must be limited to…

A: Given is a double shear connection.

Q: The structure is used to support a distributed load of w = 5 kN/m. The bolts at A, B, and C each…

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Q: The rectangular reinforced concrete column is reinforced with 6- 20 mm steel bars as shown. If b =…

A: Given Data B=250 mm D=400 mm d=20 mm(steel bar) P=400 kN

Q: The beam is supported by a pin at C and by a short link AB. Each pin has a diameter of 26 mm. Assume…

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Q: Use the graphical method to construct the shear-force diagram and identify the magnitude of the…

A: GivenP=58kNw=14 kN/mL=3mAy=45.67 kNDy=54.33 kN

Q: For the connection shown, the average shear stress in the 8-mm-diameter bolts must be limited to 170…

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Q: The structure is used to support a distributed load of w = 5 kN/m. The bolts at A, B, and C ea have…

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Q: If the allowable bearing stress for the material under the supports at A and B is o₂ = 810 psi,…

A: FBD

Q: The frame shown is supported by fixed support at E and smooth surface at A. Find: the internal…

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Q: P a

A: GIVEN DATA- 23.5-mm-diameter pin at A P = 28.36 kN, a = 2.25 m, and b = 6.56 m.

Q: Strength of materials Qz The steel shaft has a diameter of 50 mm and is fixed at end A and turn free…

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Q: Provide final answer and equations used.

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Q: The assembly is used to support the distributed load of w=500 lb/ft. determine effort normal in bar…

A: Given Force = 500 lb/ft Bar diameter = 0.4 in Bolt diameter = 0.3 in To find Normal stress in bar…

Q: Problem 4: Determine the resultant intermal loadings acting on the cross section through point B of…

A: To determine the internal reactions at point B.

Q: Q2/ Segments AB and BC of the assembly below are made from 6061-T6 aluminum. If a couple forces P= 5…

A: given: P = 5 kip

Q: allowable bearing stress for the material under the supports at A and B is σ₂ = 780 psi, determine…

A:

Q: Q4/ The aluminum bracket A is used to support the centrally applied load of 8 kip. If it has a…

A: Now draw the free body diagram of bracket,

Q: Rigid beam AB is supported by three bolts at A and a pin at B. The bolts at A are in double shear…

A:

Q: For the connection shown, the average shear stress in the 11-mm-diameter bolts must be limited to…

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Q: The two steel shafts (1) and (2) each Ø10 should be connected to each other with the help of the…

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Q: P В D F H Н y C E G A ponols ot 10 &

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Q: circular tube AB is fixed at one end andfree at the other end. The tube is subjected to axialforce…

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Q: The lap joint shown is connected by 6 pieces rivets. Assuming that the load P = 70 KN is carried…

A: Given Data Applied load is: P=70 kN=70000 N. Number of rivets are: n=6 Allowable shear stress is:…

Q: Rod BD is made of steel (E= 29 × 100 psi) and is used to brace the axially compressed member ABC.…

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Q: If a = 3 in. and the wood has an allowable normal stress of sallow = 1.5 ksi, and an allowable shear…

A: The section modulus of the rectangular cross-section about the neutral axis is…

Q: The rigid bar AB and CD are supported by pins at A and D. the vertical rods are made of aluminum and…

A: Given Data For bar AB L=4 ft A=0.75 in2 E=10×106 psi   For bar CD L=5 ft A=0.25 in2 E=12×106…

Q: The smallest allowable length L of the bearing plate is in.

A: Given data

Q: The beam is supported by a pin at Cand by a short link AB. Each pin has a diameter of 12 mm. Assume…

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Q: If the allowable bearing stress for the material under the supports at A and B is σb = 840 psi,…

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Q: The simply supported joist is used in the construction of a floor for a building. In order to keep…

A: Understand due to symmetry of the beam the reactions offered by the supports will be equal and…

Q: For the frame shown, determine the minimum bolt diameter at B if the shear stress in the bolt is…

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Q: If the allowable bearing stress for the material under the supports at A and Bis op = 820 psi,…

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Q: The assembly is used to support a 10 kN point load at the tip as shown. The steel rod has a diameter…

A: Given: The load, F = 10 kN The diameter of steel rod, D = 12 mm The diameter of steel pin, d = 8 mm…

Q: The simply supported joist is used in the construction of a floor for a building. In order to keep…

A: The given load is 600 lb =P The reaction at the supports is 600/2=300 lb The allowable shear stress…

Q: Problem 7-45: The member consists of two plastic channel strips 0.5 in. thick, glued together at A…

A: Given data:The intensity of the load, w0 = 3 kip/ft.Draw the free body diagram.

Q: Problem 7-13: Determine the maximum shear stress in the strut if it is subjected to a shear force of…

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Q: The bars of the truss each have a cross-sectional area of 1.25 in2. Determine the average normal…

A: Cross-section area of the bars = 1.24 in2 P = 6 kiP tan ϑ = 3 / 4  ϑ = tan-1 (3/4) ϑ = 36.87' Take…

Q: buted load of intensity q as shown. Consider BC. Each bar has a cross-section that is 0.75 in mal…

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Combined Loading

Any functioning component, such as machine parts, structural members, pressure vessels, and so on, are all under the influence of more than one force. When anybody is under the influence of more than one force such as shear forces, bending moments, axial forces, torsion, and so on, then such body is said to be under combined loading. A very practical example of combined loading is the crankshaft of an internal combustion engine (IC engine). The crankshaft of the IC engine is under high rpm, which is caused due to the torsional forces. Due to the presence of piston, counterbalances, and internal imbalances, the crankshaft experiences lateral forces and due to the rise in temperature, the crankshaft undergoes thermal expansion, which pulls the crankshaft along the axial direction and lateral direction. The presence of unbalanced loads along the periphery of the crankshaft also induces a bending moment.