2 kip /ft 1 kip/ft -15 ft - Prob. 7-93

-55./Draw the influence line for the force in member CJ. then compute the maximum live force (tension or compression) that can be developed in this member due to a uniform live load of 3 kN/m which is transmitted to the *6-60. E DE of th force (te- member truss along the bottom cord. transmi

F4-20. Determine the resultant couple moment acting on the triangular plate. 150 lb 91 OST 91 00 91 00 91 00 F4-20

The toggle joint is subjected to the load P. Determine the compressive force F it creates on the cylinder at A as a function of θ.

Classify structurc shown bclow as stablc or unstablc. If stablc, dcterminc whcther statically determinate or statically indeterminate. Explain your reasoning. If statically indeterminate, specify the degree of statical indeterminacy. Telles lixed

H.W-4: For the beam of sections and detail shown in Fig. find the maximum live load (PL) that the beam can be carry it. Neglect self-weight? Ans. PL=195.74 kN Use f 35 = - MPa fy 420 -2.0m- 70mm 2PL 2020mm 5025mm 350 mm sct.a-a 600 mm- a a -2.0m- -LHHH] .... .... 8025mm Soemy 3025mm 350 mm sct.b-b b b -2.0 m- 600 mm PL

1- A simply supported beam is composed of three plates, which are fastened together using bolts that are spaced at 150mm intervals in the longitudinal direction of the beam. If the allowable shear on the bolts is 15 kN, what is the maximum allowable value of the applied load P? 24 24 Bolts spaced at 150 mam P 70 longitudinally - 1.5m Бо 5m dimensions in mm 00 24 Beam crovs-section

snip

F7-21. Determine the maximum force P that can be applied to the rod if it is made of material having a yield stress of oy - 250 MPa. Consider the possibility that failure occurs in the rod and at section a-a. Apply a factor of safety of F.S. - 2 against yielding. 40 mm 50 mm 120 mim |60 mm Section a-a

MECH 1 ASSIGNMENT 1 y 10k E - 2M 20 k G C 20 k 50 Problem A truss is subjected to the following forces as shown. Determine: (a.) The magnitude of the resultant of the external forces, R (kips). D *Kip (k)-a unit of force, equivalent to 1000 lbs. (Av. AH. Bv) 20 k 15-10 I 25 25 10 15 ft ft ft ft ft In short, solve for the reactions at the supports using the equilibrium equations >Fv, ΣFH, ΣΜ (AH, Av, Bv) F 10 k 15 ft + 10 ft 25 ft B