2) How many valence electrons do the following neutral elements have? a) P b) Xe c) Ba d) C 3) Out of the following pairs, which element would you expect to have the higher electronegativity? a) Rb and Sr b) La and Co c) As and P 4) Out of the following pairs, which element would you expect to be larger? a) Rb and Sr b) La and Co c) As and P

using the given values for trial 1, how would you find the mass of pure liquid H2O2?

Ranking lonic Solutions: modified MC ChemlB Spr21 Page | 5 DI Predict the ranking of the pH for the solutions. 8) Fill in Table ID. Do this before performing the experiment with Beyond Labz Middle column: Identify cach solution as one of the following: Strong acid Weak acid Strong base Weak base Acidic salt Neutral salt Basic salt Last column: predict the pH ranking for the following 0.1 M solutions in order of expected increasing pH: rank of 1 will be for the strongest acid and the rank of 14 will be for the strongest base. Table 1D: Predicted Rank (1 most acidic and 14 most basic) Solutions (0.1IM) Identification NH,CI NaHCO3 KNO, NH3 H2SO4 NaC,H3O2 (NaAc) HCI H2SO3 HC2H3O2 (HAc) HCN NaOH NaCN H3PO4 Na PO4

To /bbhosted.cuny.edu/webapps/assessment/take/launch.jsp?course_assessment_id%3_2032634_1&course_ id= 201483.. Remaining Time: 1 hour, 09 minutes, 31 seconds. * Question Completion Status: A student makes a solution by dissolving 25.4 g of NaOH into 450 g of water. What is the mass percent (m/m) concentration of this solution? QUESTION 4 13.9 g Sodium sulfate (Na2SO4) has a solubility of in water at 20 °C. Which of the following mixtures will yield 100 mL a saturated solution at this temperature?. O 0.50 g of Na,SO4 in 1.0 mL of water O 125 g of NazSO4 in 1.0 L of water O 0.50 g NazSO, in 100 mL of water O 4.3 g Na,sO, in 100 mL of water O 17 g of Nazs04 in 0.500 L of water Click Save and Submit to save and submit. Click Save All Answers to save all answers. Save All Answers re to search 50°F Mostly sunn DELL DII home prt sc F10 F1 end inse F3 FS F9 F12 %23 %24 3 4. 5 7 8. Y D R E

No answer from Chat GPT will downvote Solve both as they are subparts. Image uploaded solution is not allowed.

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Example #3) 15mL of 2.0M HCI is mixed with 30mL of 0.75M KOH HCI + KOH → H₂O + KCI AHreaction = Substance H₂O HC1 KC1 KOH AHreaction=AHproducts- AHreactants AHreaction = (AHH20+ AHKCI) - (AHHCI + AHKOH) AHreaction = (-286 + -419 - 1kg1 Let's calculate the limiting reagent to determine how many mols of water will be formed: Remember: Volume of reactant ÷ 1000 x Molarity of reactant x mole-to-mole ratio to water Here's the first reactant: 15mL of 2.0M HCI IS 1500 * 2.0 0.03 mol HCl 30 1000 Lof LOM KOH Let's do this for the second reactant, 30mL of 0.75M KOH 0.75 0.0225 mol KOH = -)-(-164 -61 mol H₂O) x AHf in kJ/mol -286 -164 -419 -480 The limiting reagent is the compound that produced the fewest number of moles. Multiply that number of moles buy the AH reaction that was calculated above kJ/mol = -/-3725 kJ - +_ - 480 10.0225 Calcu From here on out, you are on your own! Calculate the enthalpy of reaction, and then the limiting reagent. Next multiply the enthalpy of reaction by the…

in text form with proper workings and explanation for each and every part and steps with concept and introduction no AI no copy paste remember answer must be in proper format with all working!!!!!!!