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- Solve the preceding problem if F =90 mm, F = 42 kN, and t = 40°MPaThe stresses on an element are sx= 1000 Psi. sy= 500 psi, and txy= 350 psi. Find the stresses acting on an element oriented at an angle 0 = 250. Show these stresses on the rotated element.The strength-to-weight ratio of a structural material is defined as its load-carrying capacity divided by its weight. For materials in tension, use a characteristic tensile stress obtained from a stress-strain curve as a measure of strength. For instance, either the yield stress or the ultimate stress could be used, depending upon the particular application. Thus, the strength-to-weight ratio RS/Wfor a material in tension is defined as Rs/w= in which a is the characteristic stress and 7 is the weight density. Note that the ratio has units of length. Using the ultimate stress Uas the strength parameter, calculate the strength-to-weight ratio (in units of meters) for each of the following materials: aluminum alloy 606I-T6, Douglas fir (in bending}, nylon. structural steel ASTM-A57.2, and a titanium alloy. Obtain the material properties from Tables [-1 and 1-3 of Appendix I. When a range of values is given in a table, use the average value.
- A specimen used in a coupon test is shown in the figure. The stresses on element A are known to be sy= -1500 psi. Use Mohr’s circle to: (a) Find the stresses acting on the element oriented at an angle ?? = -35°. (b) Find maximum normal and shear stresses and show them on sketches of properly oriented elements.A spherical balloon is filled with a gas. The outer diameter of the balloon is 20 in. and the thickness is 0,012 in. Calculate the maximum permissible pressure in the balloon if the allowable tensile stress and the allowable shear stress in the balloon are 1 ksi and 0.3 ksi, respectively.A simply supported beam is subjected to point load P at mid-span. The normal stress on an element at mid-span is known to be ??x= 1.5 ksi. Determine the element stresses lilt is rotated through angle ? = 450• Show these stresses on a sketch of an element oriented at that angle.
- The hollow drill pipe for an oil well (sec figure) is 6,2 in. in outer diameter and 0.75 in. in thickness. Just above the bit, the compressive force in the pipe (due to the weight of the pipe) is 62 kips and the torque (due to drilling) is 185 kip-in. Determine the maximum tensile, compressive, and shear stresses in the drill pipe.Repeat the previous problem using ? = 50° and stresses on the rotated element: sy1= 70 MPa, ??y1=-82 MPa, and tx1y1=-35 MPa.10/10 find the tensile stress in upper plate in section 3-3 5. 1 4 80 kN 80 kN 8-bolt DIA. 10 MM 80 kN 80 kN 8-bolt DIA. 10 MM 2) 300 mm 8 mm
- In a volume element with dimensions dx, dy, dz the negatíve y-face has a 2 MPa stress in the positivex-direction, a 3 MPa stress in the negative z-direction, and a 4 MPa stress in the negatíve y-direction. Which of the following describes the stresses per elasticity convention? Oyy = 4 MPa Oyr = -2 MPa 3 MPa A MPaF2 Q1) Axial displacement of point C in the system shown on the left is 0.01 cm. Find the maximum elongation of the bar and the maximum normal stress. A F1 A. GIVEN: F2 = 100 kN, (1 = 240 cm, €2= 160 cm, bi = 5 cm, bz=10 cm, h=5 cm, E=2.107 N/em², a=20 cm Note: neglect stress concentration. h bị b2 A-A sectionClear my choice Let's consider a rod having a solid circular cross-section with diameter of 4 mm and it is made of a material having a Young's modulus E= 200 Gpa and a Poisson's ratio of 0.3. If a tensile force Fis subjected to that rod cross-section, the diameter becomes 3.995 mm. determine the applied force F. Select one: O F= 5236 N OF=15708N O F= 13090 N OF=10472 N OF=4189 N O F=6283 N Clear my choice Finish attempt NEXT ACTIVITY MENG360 Test -Spring 2020-2021 Jup to