2- Find the applied force by the hydraulic cylinder in the truck shown graphically using KS: 1cm=1m, KF: 1cm=1 kN. W=25 kN
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- Find the internal force system acting on section 3 for the pin-connected frame.Find the sum of the horizontal forces in Newton if F1 = 100 N at 30 deg N of E and F2 = 80 N at 45 deg N of W.Addition of Vectors by Component Method Direction: Solve the given problem correctly Given : F₁ 200 N, 30° above +x F₂= 100 N, 45° above-x F3 = 150 N, -x F₁ = 220 N, 53° below +x Find: F (resultant force) Solution: Show your solution.
- 6 in 60° 20 in Statics Instructor A vertical force of P = 100 lb is required to remove the nail at C from the board. Determine the magnitude of the moment about B exerted by the 100 lb vertical force. Draw a free body diagram for the system. Then, use what you know about moments to solve for Mp What is the magnitude of the moment at point B due to P if P = 100 lb and 9 = 10"? Round to the nearest whole number. Enter a response then click Submit below lb inQ5: The forces F1=6 kN, F2= 5 kN, and F3= 8 kN as shown in the Figure below, all of which act on point A of the bracket, are specified in three different ways. Determine the x and y scalar components of each of the three forces. F= 500 N F = 600 N 3 35 0m 0.2 m- 03 m F = 800 N B -0.4 mFind the magnitude and direction of the resultant force for the given forces F, = 18 kN, F2 = 12 kN and F3 = 21 kN acting on hook fixed to a wall as shown in figure. Take e, = 39° & e2 = 39°. F1 F3 F2 (NOTE: ENTER ONLY THE VALUES BY REFERRING TO THE UNITS GIVEN IN THE BRACKET. ALSO, SUBMIT THE HANDWRITTEN ANSWER SHEET IN THE LINK PROVIDED) The sum of horizontal force component for the given system (unit is in kN), E =
- Find the magnitude and direction of the resultant for system of forces shown in the figure. Take F1= 40 kN, F2 = 55 kN, F3 =45 KN, F4 = 15 kN, 3 = 45° and 94 = 40° F3 F24 "L 03 e4 F₁ (NOTE: ENTER ONLY THE VALUES BY REFERRING TO THE UNITS GIVEN IN THE BRACKET) F4 The summation of horizontal component in KN is The summation of vertical component in (kN) is The magnitude of Resultant in (kN) is The direction of Resultant in degrees isThe resultant force of the three cable tensions that support the crate is R = 500j lb. Find T1 and T3, given that T2 = 300 lb. "Full procedure (step by step), please."Solve the reaction forces.
- Find the magnitude and direction of the resultant force for the given forces F, = 18 kN, F2 = 12 kN and F3 = 21 kN acting on hook fixed to a wall as shown in figure. Take e, = 39° & e2 = 39°. F1 F3 F2 (NOTE: ENTER ONLY THE VALUES BY REFERRING TO THE UNITS GIVEN IN THE BRACKET. ALS0, SUBMIT THE HANDWRITTEN ANSWER SHEET IN THE LINK PROVIDED) The sum of horizontal force component for the given system (unit is in kN), E, = The sum of vertical force component for the given system (unit is in kN), E, = The resultant of the given force system is (unit in kN), R = The direction of the resultant force (in degrees) =HOME WORK 3 Determine the resultant force at A. for the figure below Hint : 1- Find the position of all points A,B,C (x, y, z) 2- Find FAR and FAC 3- Find |raR| and Iracl 4- Find FAR = F UAB and FAC = F UAC 5- Finally find R and a, B,Y 3m Fc= 500N FB= 500N 3m 5m 3m B 4m 2m 5mQ5: The forces F1=6 kN, F2= 5 kN, and F3= 8 kN as shown in the Figure below, all of which act on point A of the bracket, are specified in three different ways. Determine the x and y scalar components of each of the three forces. F2= 500 N F = 600 N 35 0.1 m F0.2 m 03m F, = 800 N B -0.4 m-