2) Consider the function: f(t) = 0, e-kt, 0 ≤ t < 1 1 ≤t. A) Use the definition to find F(s) = L{f(t)}, where k is a constant. B) What value of k makes F(5) zero? Explain your answer.

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A: we know that ∫abf(x)dx=∫acf(x)dx+∫cbf(x)dx, where c is betwwen a and  bgiven  ∫17f(x)dx=7.2 and…

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A: fiven  F(x)=∫-3x3xz3dzwe know  ∫zndz=zn+1n+1+cdxndx=nxn-1

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