2/ Calculate the average and r.m.s values of the current waveform given by: i(t) = 100 + 25 sin 3wt + 10 sin 5wt Ans [100V, 101.8V] %3D
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- 5. Let's change our square wave to be less square. We're only going to have it be at the high voltage for 25% of the cycle. Sketch what you would expect Vout to look like now: ha n 2.T V S T 3T tA voltage wave of 250 kHz has a Vmax-5 V and Vmin=-35 V. The duty cycle of this wave is 0.875. This voltage waveform has been applied across a 2.5 µH inductor for a very long time so that steady state has been achieved. Diagrams of the wave parameters and circuit are shown in this figure: L What is the average voltage of this wave? Average voltage = 35 V Voltage (arb, unit) 1.25 Minimum current: -3.5€ Amps 1 0.75 0.5 0.25 0 4.25 05 Have you integrated the wave over full cycle? 4.75 4 -1.25 Vmax 0.5 Vmin What is the average current flowing through the inductor? Average current = 3.56 A 15 Period/s On average, there is no power consumed by the inductor. Have you considered this? What are the maximum and minimum currents that flow through the inductor? Maximum current: 0.50 Amps D= 25 TH TH Have you used the relationship for current and voltage in an inductor? Have you considered the slope of the current wave?The peak distance of a sinusoidal waveform displayed on a C.R.O. screen is 11 cm and the 'volts/cm' switch is on 38 V/cm. The peak to peak voltage is given by O 3.45 V 295.53 V 836.00 V O 209.00 V
- When measured by an analog meter, a sinusoidal voltage shows a reading of 100 Vrms. What is the amplitude of the voltage source? A 140 V B) 141 V c) 142 V D 143 VThe peak to peak distance of a sinusoidal waveform displayed on a C.R.O. screen is 9 cm and the 'volts/cm' switch is on 45 V/cm. The peak voltage is given by 405.00 V 202.50 V 5.00 V O 286.33 VAn rms voltage of 22.2 V with a frequencyof 1.00 kHz is applied to a 0.290-mH inductor. (a) What is the rmscurrent in this circuit? (b) By what factor does the current changeif the frequency of the voltage is doubled? (c) Calculate the current for a frequency of 2.00 kHz
- Q5/ Find RMS value for the wave forms below 2T 3TThe average value of a sinusoidal current is 100 ampere. What is its rms value.Shown in the figure below is an "RL" circuit drive by an AC power source. The AC power source has an RMS voltage of Vps (RMS) = 9.84 Volts and is running at a frequency of f = 8.585e+04 Hz. The resistor has a resistance of R = 2170 and the inductor has an inductance of L = 3.54e-03 Henries. Vps R ww Write the FORMULA for the total impedance of the circuit Ztot = Determine the numerical value of Ztot = 2890.5 Determine the numerical value of $z= = 41 Determine the current through the circuit: • I(PEAK) = 4.81E-3 • I(RMS) = 3.404E-3 Determine the voltage across the resistor: • VR(PEAK) = 7.387 • VR(RMS) = 5.22 ✔✔ Amps ✔Amps Write the FORMULA for the phase of the total impedance of the circuit z... = | tan-1 2701 R x Volts X Volts Determine the voltage across the inductor: • VL(PEAK) = 9.184 • VL(RMS) = 6.49 ✔ Volts Volts L R²+ WL- ✔ degrees 2 If a second circuit were connected in parallel with the inductor, this circuit would be considered as: O a low-pass filter O a capacitive switcher…
- Supply voltage has an average value of 200 V. Its RMS value is RMS value, Vrms = %3DGiven V, = 20 sin(ot + 60°) and V, = 60 cos(wt – 10°) . What is the phase angle between the waveforms? All terms to be expressed in cosine tems. 60 40 20 80A full wave rectified sinusoidal voltage is clipped at 1/√2 of its maximum value. What are the average and RMS values of such a voltage