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2-25 Find the power provided by the source and the current through the 68-k2 resistor in Figure P2-25. Px 5 A www 22 ΚΩ ww 33 ΚΩ FIGURE P2-25 68 ΚΩ

2-25 Find the power provided by the source and the current through the 68-k2 resistor in Figure P2-25. Px 5 A www 22 ΚΩ ww 33 ΚΩ FIGURE P2-25 68 ΚΩ

Introductory Circuit Analysis (13th Edition)
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
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2.25 EXAMPLE 2-25 Use series and parallel equivalence to find the output voltage no and the input car- rent is in the ladder circuit shown in Figure 2-53(a) SOLUTION: One approach is to combine parallel resistors and use voltage division to find o and then combine all resistances into a single equivalent to find the input current is Figure 2-53(b) shows the step required to determine the equivalent resistance between the terminals B and ground. The equivalent resistance of the parallel 2R and R resistors is REQ= The reduced circuit in Figure 2-53(b) is a voltage divider. Notice that the two nodes needed to find the voltage wo. nodes B and ground, have been retained. The unknown voltage is found in terms of the source voltage as 10=5 Rx2R 2, R-2R R 5 A R+R The input current is found by combining the equivalent resistance found previously with the remaining resistor R to obtain By M. -- RE=R+REQ 2. 5. = RR=R Application of series/parallel equivalence has reduced the ladder circuit to the single equivalent resistance shown in Figure 2-53(c). Using Ohm's law, the input current is 2 By R 3.0 5 R Notice that the reduction step between Figure 2-53(b) and (c) eliminates node B, so the output voltage no must be calculated before this reduction step is taken. 2-25 Find the power provided by the source and the current through the 68-k2 resistor in Figure P2-25. 22 ΚΩ w 33 ΚΩ FIGURE P2-25 w R 68 ΚΩ· 28/3 SRS FIGURE 2-53 (0) w W (c)
Transcribed Image Text:2.25 EXAMPLE 2-25 Use series and parallel equivalence to find the output voltage no and the input car- rent is in the ladder circuit shown in Figure 2-53(a) SOLUTION: One approach is to combine parallel resistors and use voltage division to find o and then combine all resistances into a single equivalent to find the input current is Figure 2-53(b) shows the step required to determine the equivalent resistance between the terminals B and ground. The equivalent resistance of the parallel 2R and R resistors is REQ= The reduced circuit in Figure 2-53(b) is a voltage divider. Notice that the two nodes needed to find the voltage wo. nodes B and ground, have been retained. The unknown voltage is found in terms of the source voltage as 10=5 Rx2R 2, R-2R R 5 A R+R The input current is found by combining the equivalent resistance found previously with the remaining resistor R to obtain By M. -- RE=R+REQ 2. 5. = RR=R Application of series/parallel equivalence has reduced the ladder circuit to the single equivalent resistance shown in Figure 2-53(c). Using Ohm's law, the input current is 2 By R 3.0 5 R Notice that the reduction step between Figure 2-53(b) and (c) eliminates node B, so the output voltage no must be calculated before this reduction step is taken. 2-25 Find the power provided by the source and the current through the 68-k2 resistor in Figure P2-25. 22 ΚΩ w 33 ΚΩ FIGURE P2-25 w R 68 ΚΩ· 28/3 SRS FIGURE 2-53 (0) w W (c)
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