1)What is the electric potential due to the nucleus of hydrogen at a distance of 6.50×10-11 m? Assume the potential is equal to zero as r→∞. (Express your answer to three significant figures.)

Throughout this problem, consider a charge configuration consisting of a proton fixed in place at position (x,y) = (-1nm, -1nm) and an electron fixed in place at point (x,y) = (1nm, 1nm). Draw the configuration of charges described above, and without calculation, sketch an estimate of what you believe the graph of electric potential V (x) looks like as a function along the x-axis from x = -10nm to x= 10nm. NOTE: it is helpful to draw two diagrams. One representing the location of charges in physical (x,y) space, and the other representing the function of the potential V(x), that you create by estimating the electric potential at various locations along the x-axis.

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you have a nucleus with 19 protons, placed at x = 3.6 Angstroms. What what TWO values of x (along the x-axis) will the total electrostatic potential V be equal to zero?

If you already know the electric field, you can find the change in electrostatic potential between two points A and B by integrating the field along an arbitrary path joining these two points, VB - VA = while the field at r > R is == E(r) = 1 Recall from Gauss's law that the magnitude of the electric field E(r) at a radial distance r ≤R from the center of a uniformly charged sphere with total charge Q and radius R is given by E(r) = B Ē. ds. 1 Q 4π€0 R3¹ 1 Q p2 4πεο If the charge Q is positive, the field points radially out. We will now analyze the electric potential due to a uniform spherical charge distribution.

Q-2: Two concentric conducting spherical shells of radii r¡ and r, > rz. The inner shell carries a charge +Q while the outer shell carries a charge +2Q as shown. Assuming V = 0 as r → ∞, Calculate: a. The electric field vectors: E1(r r2) b. The electric potentials: V, (r r2) c. The electric potential difference between the two shells: AV

Now you have a nucleus with 19 protons, placed at x = 5.1 Angstroms. What TWO values of x (along the x-axis) will the total electrostatic potential V be equal to zero?     0.28 Angstroms and -0.26 Angstroms     -0.11 Angstroms and 0.08 Angstroms     0.11 Angstroms and -0.08 Angstroms     -0.28 Angstroms and 0.26 Angstroms

Now you have a nucleus with 16 protons at x = 2.7 Angstroms on the x-axis. What is the value of the electrostatic potential V at a point on the positive y-axis, at y = 3.1 Angstroms?

Now you have a nucleus with 5 protons at x = 2.0 Angstroms on the x-axis. What is the value of the electrostatic potential V at a point on the positive y-axis, at y = 3.3 Angstroms?     7.2 V     14.3 V     -4.4 V     18.6 V

k₂Q Inside a conducting sphere with charge Q and radius R, the electric potential is given by V = the electric field inside and outside the sphere. (Use the following as necessary: ker Q, rand R.) (a) inside E₁ = (b) outside E(r> R) = and outside it is given by V = keq Using Er = dv dr I derive an expression for the magnitude of