1R,2S-dibromocyclododecane from acetylene and anything with 10 carbons or less. To do this problem, you must realize that a 12-membered ring unlike cyclohexene can be Z or E. Think of cyclohexene which only exists as the "Z" form and what product it forms with Br2 or maybe better, 2-butene which has two possible diastereomers and which diastereomer would form 2R,3S-dibromobutane.

Organic Chemistry
8th Edition
ISBN:9781305580350
Author:William H. Brown, Brent L. Iverson, Eric Anslyn, Christopher S. Foote
Publisher:William H. Brown, Brent L. Iverson, Eric Anslyn, Christopher S. Foote
Chapter2: Alkanes And Cycloalkanes
Section: Chapter Questions
Problem 2.46P
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Supply synthetic routes to the following molecules using the indicated starting materials

1R,2S-dibromocyclododecane from acetylene and anything with 10 carbons or less. To do this problem,
you must realize that a 12-membered ring unlike cyclohexene can be Z or E. Think of cyclohexene
which only exists as the "Z" form and what product it forms with Br2 or maybe better, 2-butene which has
two possible diastereomers and which diastereomer would form 2R,3S-dibromobutane.
Transcribed Image Text:1R,2S-dibromocyclododecane from acetylene and anything with 10 carbons or less. To do this problem, you must realize that a 12-membered ring unlike cyclohexene can be Z or E. Think of cyclohexene which only exists as the "Z" form and what product it forms with Br2 or maybe better, 2-butene which has two possible diastereomers and which diastereomer would form 2R,3S-dibromobutane.
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