17. Mutation can be caused by the alternative base pairing that arise due to tautomerization and deamination of cysteine and adenine. Draw the alternative base pairing. The thymine dimers can be formed by UV radiation. Alternate base pairing with enol tautomer of T Alternate base pair with deaminated A Thymine dimers due to UV radn (draw structure below) repaired by the enzyme Methylated cytosine and adenine in mismatch repair
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- Given the following diagram of how protein AWESOME1 binds to it's target DNA, describe the potential effects of each of the 5 mutations shown below. The wild-type sequence of a helix #1 is also shown in the blue box, and all the mutations are in helix #1 (see numbers for identifying particular residues). a helix #1 R(1)-V-I-L-Y-F-W-I-M-Y-F-S-H-Y-W-R(16) #1 Predict the consequence of the following mutations: 1) Arg(1) to Glu 2) Arg(1) to Ala 3) Phe(6) to lle 4) Trp(7) to Phe 5) Met(9) to Pro in3. The trp repressor is a homodimer with 107 amino acid residues per monomer. The content of proton dissociable groups of each monomer is given below: Side chain pKa number/monomer ZpH 4 ZpH 6 12.5 Arginine Aspartate Glutamate 9. 4.0 4.0 10 Histidine 6.0 2 Lysine Tyrosine -NH3® 10.0 6 9.5 2 7.0 1 -СООН 4.0 1 (a) ( : ) The isoelectric point (pl) of the protein, i.e., the pH at which the overall electrostatic charge on the protein E z = 0, is 5.3. Although the pKa values in the table above are only approximate values generally characteristic of residues with unhindered exposure to solvent, confirm that the overall charge on the protein must pass through zero between pH 4 and pH 6. ) Estimate what must be the average pKa value of all of the residues containing carboxylic (b) ( acid groups using the H-H equation below, assuming that the pka values of the positively charged groups do not change from the values given in the table above: pH pKa log [base]/[acid] + DNA teGiven the following Wild Type and Mutated DNA sequences: 1.) Identify where the base pair change occurs (what letters changed?) 2.) For BOTH sequences, write the mRNA strands, define the codon regions (with spaces), and amino acid sequences. 3.) Describe what kind of mutation has occurred (missense, nonsense, or silent), and what effect this may have on the protein. Wild Type DNA Sequence: 3' - CCTCGTTATGTG - 5' Mutated DNA Sequence: 3' - CCTCGTTATTTG - 5'
- 1. Explain why the primary structure sequence -Lys-Leu-Trp-Asp- may promote a-helix formation while the sequence -Lys-Leu-Trp-Arg- may inhibit it.2 a) The following nucleotide sequence is found on the template strand of DNA: 3-TAC TGG CCG TTA GTT GAT ATA ACT-5" Determine the amino acids of the encoded peptide, then provide the altered amino acid sequence of protein that would result from each of the following mutations and provide their classification (eg. Missense, nonsense, etc). 益券 A transition at nucleotide 11 A transition at nucleotide 13 A one-nucleotide deletion at nucleotide 7 AT to A transversion at nucleotide 15 An addition of TGG after nucleotide 6 A transition at nucleotide 91.Draw these phosphorylated structures as they would be connected in a polinucleotide (e.g.RNA) in the order A-B. / Show how they combine to form the polynuleotide (i.e. only the end product). Show at any one of these structures where the glycosidic bond occurs 2.Sanger sequencing revealed the sequence of an oligonucleotide to be: d-AGATGCCTGACT. Draw a diagram of the gel banding pattern post capillary electrophoresis i.e. where on the gel would the fragments feature
- a) It is known that double stranded DNA is denatured at low pH. pKa values should allow the determination of whether this is due to perturbation of the hydrogen bonding in A-T and/or G-C base pairs. The table gives values for the pKas of different protonated groups in the nucleobases.Nucleobase Position & pKa A N1, 3.5 G N7, 1.6; N1, 9.2 C N3, 4.2 T N3, 9.7a) Draw the A-T and G-C base pairs. - Label the bases with the one-letter code. – - Number the atoms in the rings and label the atom that attaches to the sugar. - Mark the groups that interact in normal…2. Of the two sequences, which is more likely to have helical structure. Explain. a) -Glu-Asp-Glu-Glu-Asp-Leu- b) -Glu-Leu-Asp-Arg-Val-Lys-It is known that double stranded DNA is denatured at low pH. pKa values should allow the determination of whether this is due to perturbation of the hydrogen bonding in A-T and/or G-C base pairs. The table gives values for the pKas of different protonated groups in the nucleobases.Nucleobase Position & pKa A N1, 3.5 G N7, 1.6; N1, 9.2 C N3, 4.2 T N3, 9.7a) Draw the A-T and G-C base pairs. - Label the bases with the one-letter code. – - Number the atoms in the rings and label the atom that attaches to the sugar. - Mark the groups that interact in normal…
- 34. Draw double-stranded DNA (two basepairs long with one AT basepair and one GC basepair). Your drawing should be flat; do not draw the twist of the helix. Be sure to include the 5’-P, 3’- OH, deoxyribose sugar rings (with carbons 1’-5’ and the O indicated), and a simplified phosphodiester bond (O-P-O). Show purines as two differently-sized rings and pyrimidines as one ring and show the correct number of hydrogen bonds between bases. The dsDNA must be antiparallel. Drawing a simplified version of dsDNA will help you gain a better understanding of the concepts underlying dsDNA structure. It will most likely take a couple of tries to get a clear figure.Given the following Wild Type and Mutated DNA sequences: 1.) Identify where the base pair change occurs ( what letter changed?) 2.) For BOTH sequences, write the mRNA strands, define the codon regions and amino acid sequences. 3.) Describe what kind of mutation has occurred (missense, nonsense, or silent), and what effect this may have on the protein. Wild Type DNA Sequence: 3' - AGGCTCGCCTGT - 5' Mutated DNA Sequence: 3' - AGTCTCGCCTGT - 5'1. What is the length in AA’s of the LilP protein? Assume fMet is NOT CLEAVED. 2. Write out the sequence of the polypeptide in AA: use the three letter notation, e.g. Met-Ser-Pro-