17 male and 20 female undergraduate students are randomly selected from the faculty of mechanical engineering. The summary of Test 2 EQT271 results are as follows: Male: XM = 82, SM = 8 Female: = 76, SF = 6 XF Assumed that both populations are normally distributed and the population variances are equal. Construct a 95% confidence interval (CI) for the difference in the mean score between all male and female students who took the test. Then, assumed that the population variances are not equal. Construct the 501

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Answer (1.32, 10.68), (1, 11)

17 male and 20 female undergraduate students are randomly selected from
the faculty of mechanical engineering. The summary of Test 2 EQT271 results
are as follows:
Male: XM = 82, SM = 8
Female: XF = 76, SF = 6
Assumed that both populations are normally distributed and the population
variances are equal.
Construct a 95% confidence interval (CI) for the difference in the mean score
between all male and female students who took the test.
Then, assumed that the population variances are not equal. Construct the
95% CI.
Transcribed Image Text:17 male and 20 female undergraduate students are randomly selected from the faculty of mechanical engineering. The summary of Test 2 EQT271 results are as follows: Male: XM = 82, SM = 8 Female: XF = 76, SF = 6 Assumed that both populations are normally distributed and the population variances are equal. Construct a 95% confidence interval (CI) for the difference in the mean score between all male and female students who took the test. Then, assumed that the population variances are not equal. Construct the 95% CI.
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