I need the answer as soon as possible how to solveequations→ 162%= z°(8A+4c+2D)+zY-6A+8B-C-D)+=(A-6B+4C+20)+(B-c-D)Equating the coefficients, we aet8A + 4C +2D =0-6A +8B - C - D=16A- 6B +4C+2D =0B-C- D=032A=- 9685112•:solving, we aet%3D

Answered: Image /qna-images/answer/61dd8992-1ca7-4a20-9932-19c15ca9cfb4.jpg

Answered: 162%= z3(8A+4C+2D)+zY-6A+:…

Advanced Engineering Mathematics

10th Edition

ISBN:9780470458365

Author:Erwin Kreyszig

Publisher:Erwin Kreyszig

Chapter2: Second-order Linear Odes

Section: Chapter Questions

Problem 1RQ

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162%= z3(8A+4C+2D)+zY-6A+: +=(A-6B+4C+2D)+(B-c-D) quating the coefticients, we et 8A + 4C+2D =0 -6A +8B - C - D=16 A- 6B +4C+2D =0 B-C- D 112 •:Solving, we gel 96, 85 B= c-D=-# A =- %3D